1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tekilochka [14]
3 years ago
8

You see lightning and 30 seconds later you hear thunder. how far away is the thunderstorm? take the speed of sound to be 339 m/s

. g
Physics
1 answer:
Jobisdone [24]3 years ago
3 0
Let the observer be 'd' distance away from the thunderstorm and let light take 't' time to reach the observer
Since the speed of sound and light remains constant in a particular medium, we can use
      Speed = Distance/Time

For light,
   3 x 10^8 = d/t
                t = d/(3 x 10^8)   -1 

For sound,
           339 = d/(t + 30)       -2

Putting value from 1 in 2.
               d = 10^4 m(approx)
You might be interested in
Which vector has an x-component with a length of 4?
Masja [62]

Answer:ITS Y

Explanation:

6 0
4 years ago
A mole of water molecules would just about fill a
Strike441 [17]

Answer:

B. tablespoon

Explanation:

Considering the question given, a mole of water is small compare to the options given from the question aside the table spoon.

A mole of water is just 18g and that's equivalent to 18 mL.

18 mL of water will fill a table spoon but not a cup which is about 237mL. The wheel barrow and gallon bucket have larger volumes of which 18 mL of water will never fill them.

So, a mole of water can successfully fill a table spoon.

5 0
3 years ago
What is the approximate weight of a 20-kg cannonball on Earth? 2 N 20 N 196 N 1,960 N
Margaret [11]
Since weight is the force an object is exerting on another object, and the formula to calculate force is Force = Mass * Acceleration, the answer to your question is 196 N, since the mass of the cannonball times Earth's gravitational pull equals 196 N.
5 0
4 years ago
Read 2 more answers
Một nhà máy điện hơi nước nhận nhiệt từ một lò nung với tốc độ 280(gj/h) . Tổn thất nhiệt cho không khí xung quanh khi nó đi qua
weeeeeb [17]

what is languange?????

6 0
3 years ago
If Earth orbited the Sun in 9 months instead of 12, then, compared with a sidereal day, a solar day would be
Tcecarenko [31]

Answer:

longer

Explanation:

The relationship between the solar day and sidereal is as follows:

The length of the sidereal day is

= (Solar day) (solar year ÷ solar year +  1 day)

As it can be seen that the day i.e. solar its length would be greater as compared with the sidereal day.

In the case when the earn orbited the sun in 9 months rather than 12 so here the sidereal day would be the similar but the solar day would be longer as compared with the original one

7 0
3 years ago
Other questions:
  • A solution that contains all the solute it can hold under the given conditions is ____.
    7·1 answer
  • All of the following measure volume except
    14·2 answers
  • Calculate the time (in seconds) needed for a car to accelerating from 0 m/s to 10 m/s at 5 m/s^2?
    6·1 answer
  • A force of 6N and another of 8N can be applied together to produce the effect of how much newtons?
    8·2 answers
  • In a chemical equation, numbers often appear in front of a chemical formula. What do these numbers indicate?
    15·1 answer
  • Please help me out
    12·1 answer
  • Gravity is a force between any two objects with mass. Why doesn't a person feel a gravitational force between him/herself and an
    7·1 answer
  • A potato and raisins salad has been warmed up to a temperature of 80∘C and let it stand for three minutes. Then one tries a bite
    14·1 answer
  • a 28.7 KG sled is pulled forward with a 63 net force across the ground with MK equals 0.169 what is the acceleration of the sled
    7·1 answer
  • Inside a material with an index of refraction not equal to 1, both the speed and the wavelength of light must change. is the wav
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!