Please help!!!A. 19.63B.52.5C.4.81D.22.32

Mathematics

1 answer:

anygoal [31]3 years ago

8 0

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Can someome explain to me how to do 16 and 17? Thank you so much!

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16) First solve like a normal equation.
3|x/9| - 1 = 2
3|x/9| = 3
|x/9| = 1
Now just separate into two equations:
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17) Solve like normal:
-4 - 2|b - 10| = -6
-2 |b - 10| = -2
|b - 10| = 1
Now just separate into two equations:
b - 10 = 1
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So then b = 11, 9

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Find the perimeter of the pentagon with vertices M(-2,5), N(2,5), P (5, 3),

wlad13 [49]

The perimeter of the pentagon is approximately 19.6.

<h3>Procedure - Determination of the perimeter of a pentagon</h3><h3 />

In this question we must plot the locations of each vertex on a Cartesian plane to determine the line segments that form the perimeter, whose lengths are determined by Pythagorean theorem and sum the resulting values to find the perimeter.

According to the image attached below, the line segments of the pentagon are MN, NP, PQ, QR and RM. By Pythagorean theorem we have the following lengths:

<h3>Line segment MN</h3><h3 /><h3> $l_{MN} = \sqrt{[2-(-2)]^{2}+(5-5)^{2}}$ </h3><h3> $l_{MN} = 4$ </h3><h3 /><h3>Line segment NP</h3><h3 /><h3> $l_{NP} = \sqrt{(5-2)^{2}+(3-5)^{2}}$ </h3><h3> $l_{NP} = \sqrt{13}$ </h3><h3 /><h3>Line segment PQ</h3><h3 /><h3> $l_{PQ} = \sqrt{(5-5)^{2}+(0-3)^{2}}$ </h3><h3> $l_{PQ} = 3$ </h3><h3 /><h3>Line segment QR</h3><h3 /><h3> $l_{QR} = \sqrt{(3-5)^{2}+(3-0)^{2}}$ </h3><h3> $l_{QR} = \sqrt{13}$ </h3><h3 /><h3>Line segment RM</h3><h3 />

$l_{RM} = \sqrt{(-2-3)^{2}+(5-3)^{2}}$