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damaskus [11]
3 years ago
15

A person who weighs 670 N steps onto a spring scale in the bath- room, and the spring compresses by 0.79 cm. (a) What is the spr

ing con- stant
Physics
1 answer:
andrew-mc [135]3 years ago
4 0

Answer:

The spring constant is 84,810.13 N/m

Explanation:

Given;

applied force on the spring scale, f = 670 N

extention of the spring, x = 0.79 cm = 0.0079 m

Apply Hook's law to determine the spring constant;

f = kx

where;

f is the applied force

k is the spring constant

x is the is the extension

k = f / x

k = 670 / 0.0079

k = 84,810.13 N/m

Therefore, the spring constant is 84,810.13 N/m

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a meteor is falling towards the earth. If the mass and radius of the earth are 6×10^24 kg and 6.4×10^6 m respectively. Find the
ELEN [110]

Answer:

3.6×10⁶ m

Explanation:

Newton's law of universal gravitation states that the force between two masses is:

F = GMm / r²

where G is the universal constant of gravitation (6.67×10⁻¹¹ m³/kg/s²),

M is the mass of one object

m is the mass of the other object,

and r is the distance between the center of masses of the objects.

The force acting on the meteor is:

∑F = ma

GMm / r² = ma

GM / r² = a

Given M = 6×10²⁴ kg and a = 4 m/s²:

(6.67×10⁻¹¹ m³/kg/s²) (6×10²⁴ kg) / r² = 4 m/s²

r = 10⁷ m

The distance from the meteor to the center of the Earth is 10⁷ m.  We want to know what the height of the meteor is (distance to the surface of the Earth).  So we need to subtract the Earth's radius.

h = 10⁷ m − 6.4×10⁶ m

h = 3.6×10⁶ m

7 0
3 years ago
An astronaut rides in a circular training accelerator at 16 m/s. If the radius of the accelerator is 8.0 meters, what is his cen
iren [92.7K]

Answer:

a=32\ m/s^2

Explanation:

Given that,

The velocity of an astronaut in a circular path, v = 16 m/s

The radius of the accelerator, r = 8 m

We need to find his centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{8}\\\\a=32\ m/s^2

So, the required centripetal acceleration is 32\ m/s^2.

7 0
3 years ago
Which of the following statements are true? Positively charged objects attract other positively charged objects. Negatively char
butalik [34]
The statement that is true is that positively charged objects attract negatively charged objects. This is due to a law that states 'like forces attract while unlike forces repel. This same concept applies to magnetism. If you put two similar poles together, for example; if you place two south poles together. You feel a separating force between the two poles. But if you place two opposite poles together they attract each other. Hope i helped. <span />
7 0
3 years ago
Read 2 more answers
An electron and a proton each have a thermal kinetic energy of 3kBT/2. Calculate the de Broglie wavelength of each particle at a
IgorLugansk [536]

Answer:

The de Broglie wavelength of electron βe = 2.443422 × 10⁻⁹ m

The de Broglie wavelength of proton βp = 5.70 × 10⁻¹¹ m

Explanation:

Thermal kinetic energy of electron or proton = KE

∴ KE = 3kbT/2

given that; kb = 1.38 x 10⁻²³ J/K , T = 1950 K

so we substitute

KE = ( 3 × 1.38 x 10⁻²³ × 1950 ) / 2

kE = 4.0365 × 10⁻²⁰ (  is the kinetic energy for both electron and proton at temperature T )

Now we know that

mass of electron M'e = 9.109 ×  10⁻³¹

mass of proton M'p = 1.6726 ×  10⁻²⁷

We also know that

KE = p₂ / 2m

from the equation, p = √ (2mKE)

{ p is momentum, m is mass }

de Broglie wavelength = β

so β = h / p = h / √ (2mKE)

h = Planck's constant = 6.626 ×  10⁻³⁴

∴ βe =  h / √ (2m'e × KE)

βe = 6.626 ×  10⁻³⁴ / √ (2 × 9.109 ×  10⁻³¹ × 4.0365 × 10⁻²⁰ )

βe = 6.626 ×  10⁻³⁴ / √  7.3536957 × 10⁻⁵⁰

βe = 6.626 × 10⁻³⁴  / 2.71176984642871 × 10⁻²⁵

βe = 2.443422 × 10⁻⁹ m

βp =  h / √ (2m'p ×KE)

βp = 6.626 ×  10⁻³⁴ / √ (2 × 1.6726 ×  10⁻²⁷ × 4.0365 × 10⁻²⁰ )

βp = 6.626 ×  10⁻³⁴ / √ 1.35028998 × 10⁻⁴⁶

βp =  6.626 ×  10⁻³⁴ / 1.16201978468527 ×  10⁻²³

βp = 5.702140 × 10⁻¹¹ m

3 0
3 years ago
g A circular loop of wire with radius 3 m is flat on the xy plane in a magnetic field which is pointed in the z-direction and ha
Phantasy [73]

Answer:

emf=-0.035V

Explanation:

this problem can be solved with the Lenz's law:

emf=-\frac{\Delta \Phi_{B}}{\Delta t}

where PhiB is the magnetic flux. In this case we have

\Delta \Phi_{B}=B(A_1-A_2)

due to the magnetic field is constant. A is the area of the circular loop. Hence

\Delta \Phi_{B}=(5*10^{-3}T)(\pi(3m)^2-\pi(1.5m)^2)=0.106Tm^2

Finally

emf=-\frac{0.106Tm^2}{3s}=-0.035V

HOPE THIS HELPS!!

7 0
3 years ago
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