Answer:
6.85 g
Explanation:
Step 1: Given data
- Molar concentration of the solution: 0.200 M (0.200 mol/L)
- Volume of the solution: 100.00 mL (0.10000 L)
Step 2: Calculate the moles of sucrose (solute) required
Molarity is equal to the moles of solute divided by the liters of solution.
M = moles of solute / liters of solution
moles of solute = M × liters of solution
moles of solute = 0.200 mol/L × 0.10000 L = 0.0200 mol
Step 3: Calculate the mass corresponding to 0.0200 moles of sucrose
The molar mass of sucrose is 342.3 g/mol.
0.0200 mol × 342.3 g/mol = 6.85 g
