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barxatty [35]
2 years ago
15

An aqueous sucrose (C12H22O11) solution must be created for an experiment. If 100.00 mL of 0.200 M solution is needed, what amou

nt of sucrose (in grams) must be weighed out
Chemistry
1 answer:
AnnZ [28]2 years ago
4 0

Answer:

6.85 g

Explanation:

Step 1: Given data

  • Molar concentration of the solution: 0.200 M (0.200 mol/L)
  • Volume of the solution: 100.00 mL (0.10000 L)

Step 2: Calculate the moles of sucrose (solute) required

Molarity is equal to the moles of solute divided by the liters of solution.

M = moles of solute / liters of solution

moles of solute = M × liters of solution

moles of solute = 0.200 mol/L × 0.10000 L = 0.0200 mol

Step 3: Calculate the mass corresponding to 0.0200 moles of sucrose

The molar mass of sucrose is 342.3 g/mol.

0.0200 mol × 342.3 g/mol = 6.85 g

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Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

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