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2 years ago

6

An airplane which intends to fly due south at 250 km/hr experiences a wind blowing westward at 40 km/hr. What is the actual spee

d of the airplane relative to the ground?

1 answer:

sleet_krkn [62]2 years ago

7 0

Answer:

simple is rumple a daily ok I'll be

You might be interested in

If it takes 600 N to move a box 5 meters, how much work is done on the box?

Anika [276]

Answer:

<h2>3000 J</h2>

Option C is the correct option.

Explanation:

Given,

Force = 600 N

Distance = 5 meters

Work = ?

Now,

Work = Force $\times$ distance

$= 600 \times 5$

Calculate the product

$= 3000 \:$ Joule

Hope this helps...

Good luck on your assignment..

3 0

3 years ago

Read 2 more answers

In a hydroelectric power plant, water flows from an elevation of 400 ft to a turbine, where electric power is generated. For an

VashaNatasha [74]

Answer:

$V=3.475ft^3/s=3.48ft^3/s$

Explanation:

We have here values from SI and English Units. I will convert the units to English Units.

We hace for the power P,

$P= 100kW \rightarrow 100kW*(\frac{737.56ft.lbf/s}{1kW})$

$P= 73.7*10^{3}ft.lbf/s$

we have other values such $h=400ft$ and $\gamma= 62.42lb/ft^3$ (specific weight of the water), and 0.85 for \eta

We need to figure the flow rate of the water (V) out, that is,

$V=\frac{P}{\gamma h \eta_0}$

Where $\eta_0$ is the turbine efficiency, at which is,

$\eta_0 = \frac{P}{\gamma Vh}$

Replacing,

$V=\frac{73.7*10^{3}}{62.42*400*0.85}$

$V=3.475ft^3/s$

With this value (the target of this question) we can also calculate the mass flow rate of the waters,

through the density and the flow rate,

$m=\rho V\\m= 3.475*1.94 \\m=6.7415 slugs/s$

converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,

$m= 217lbm/s$

6 0

2 years ago

calculate the average acceleration of a car with a starting velocity of 0 m/s that accelerates to 9 m/ s in 3 second

ladessa [460]

Answer:

a = 3 m/s²

Explanation:

a = Δv/t

a = (vf - vi)/t

a = (9 - 0)/3

a = 3m/s²

6 0

2 years ago

Calculate the momentum of a 10 kg bowling ball rolling at 2m/s towards north.

densk [106]

Answer:

momentum=mass x velocity= 10 x 2 = 20kgm/s

8 0

2 years ago

An object oscillates back and forth on the end of a spring. Which of the following statements are true at some time during the c

Sindrei [870]

Answer:

a. The object can have zero acceleration and, simultaneously, nonzero velocity.

c. The object can have nonzero velocity and nonzero acceleration simultaneously.

d. The object can have zero velocity and, simultaneously, nonzero acceleration.

Explanation:

For an object in simple harmonic motion, the total mechanical energy (sum of elastic potential energy and kinetic energy) is constant:

$E=U+K=\frac{1}{2}kx^2 + \frac{1}{2}mv^2$ (1)

where

k is the spring constant

x is the displacement

m is the mass

v is the speed

We can also notice that the force on the spring is given by Hook's law:

$F=-kx$

And since according to Newton's law we have F = ma, this can be rewritten as

$ma=-kx\\a=-\frac{k}{m}x$

which means that the acceleration is proportional to the displacement.

So by looking again at eq.(1), we can now states that:

- when the displacement is zero, x=0, the acceleration is zero, a=0, and the velocity is maximum

- when the velocity is zero, v=0, the acceleration is maximum, which occurs when the displacement is maximum

- in all the other intermediate situations, both velocity and acceleration are non-zero

So the correct answers are

a. The object can have zero acceleration and, simultaneously, nonzero velocity.

c. The object can have nonzero velocity and nonzero acceleration simultaneously.

d. The object can have zero velocity and, simultaneously, nonzero acceleration.

8 0

2 years ago