Answer:Work is a measurement of energy.
Power is a measurement of energy per time.
So, power measures how fast work is done.
If we raise 1kg up to a height of 1 meter it takes a certain amount of work. It doesn't matter if it takes us 1 second or 1 hour to raise it. It takes more power, energy per second, to raise it in 1 second than to raise it in one hour.
An engines power rating is in horsepower. A higher horsepower car engine will get a certain car up a hill more quickly than if it had a lower horsepower engine. Even though both engines did the same amount of work in getting the car up the hill
Answer:
The highest electric field is experienced by a 2 C charge acted on by a 6 N electric force. Its magnitude is 3 N.
Explanation:
The formula for electric field is given as:
E = F/q
where,
E = Electric field
F = Electric Force
q = Charge Experiencing Force
Now, we apply this formula to all the cases given in question.
A) <u>A 2C charge acted on by a 4 N electric force</u>
F = 4 N
q = 2 C
Therefore,
E = 4 N/2 C = 2 N/C
B) <u>A 3 C charge acted on by a 5 N electric force</u>
F = 5 N
q = 3 C
Therefore,
E = 5 N/3 C = 1.67 N/C
C) <u>A 4 C charge acted on by a 6 N electric force</u>
F = 6 N
q = 4 C
Therefore,
E = 6 N/4 C = 1.5 N/C
D) <u>A 2 C charge acted on by a 6 N electric force</u>
F = 6 N
q = 2 C
Therefore,
E = 6 N/2 C = 3 N/C
E) <u>A 3 C charge acted on by a 3 N electric force</u>
F = 3 N
q = 3 C
Therefore,
E = 3 N/3 C = 1 N/C
F) <u>A 4 C charge acted on by a 2 N electric force</u>
F = 2 N
q = 4 C
Therefore,
E = 2 N/4 C = 0.5 N/C
The highest field is 3 N, which is found in part D.
<u>A 2 C charge acted on by a 6 N electric force</u>
Answer:
h = 6.371 m
Explanation:
Data:
Potential Energy = P.E = 1500 J
Mass = m = 24 Kg
Gravity = g = 9.81 m/sec²
Height = h = ?
Solution:
As the formula for the Potential Energy is;
P.E = mgh
Replacing the values in the above equation
1500 = 24 × 9.81 × h
h = (1500)÷(24 × 9.81)
h = 6.371 m
Answer:
Option (E) 38 ohm
Explanation:
Voltage, V = 4.5 V
Current, i = 0.12 A
Let r be the resistance of the filament of the bulb.
By use of Ohm's law
V = i x R
4.5 = 0.12 x R
R = 4.5 / 0.12 = 37.5 Ohm
By rounding off
R = 38 ohm