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andreev551 [17]
3 years ago
15

How does the redshift of distant galaxies best support the big bang theory? It shows that the galaxies are becoming warmer. It s

hows that the galaxies are becoming larger. It shows that the galaxies are moving farther away. It shows that the galaxies are shrinking in size.
Physics
2 answers:
Elan Coil [88]3 years ago
7 0
It shows that galaxies are moving further away
cupoosta [38]3 years ago
5 0

Answer:

It shows that the galaxies are moving farther away.

Explanation:

When light from the galaxies is shifted towards the longer wavelengths, it is called red shift. When light shifts towards the shorter wavelengths, it is called blue shift. Big bang theory states how the primordial universe started expanding from a hot and dense singularity, in the process of evolution of the universe.

The  universe is expanding always. Galaxies that are a part of the universe keep expanding and move farther away from each other. The galaxies that are very far off appear to  move much faster than the nearby galaxies.

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Cuál es la resistencia de un foco que está conectado a una fuente de 20 v por el cuál pasa una intensidad de 20 mA
LUCKY_DIMON [66]

Answer:

The resistance of the bulb is 1000 ohms.

Explanation:

What is the resistance of a bulb that is connected to a 20 v source through which a current of 20 mA passes

We have,

Voltage of the bulb is 20 V and the current passes is 20 mA.

It is required to find the resistance of the bulb. The relation between resistance, current and voltage is given by using Ohm's law as :

V =  IR

R is resistance

R=\dfrac{V}{I}\\\\R=\dfrac{20}{20\times 10^{-3}}\\\\R=1000\ \Omega

So, the resistance of the bulb is 1000 ohms.

7 0
2 years ago
Hey any physicist or engineer around. am giving brainliest to anyone who will answer this question.
Oduvanchick [21]

Answer:

N = 167 Newtons

R = 727 Newtons

Explanation:

i) For static equilibrium, moments about any convenient point must sum to zero.

A moment is the product of a force and a moment arm length. Only the force acting perpendicular to a moment arm passing through the pivot point makes a moment.

ii) I will <em>ASSUME </em>the two moment arms are 0.05m and 0.15 m

CCW moments about the fulcrum are

190 N(0.2 m) + 280 N(0.05 m) = 52 N•m

CW moments are (N)N(0.15 m + 90 N(0.3 m) = 27 + 0.15N N•m

For static equilibrium, these must be equal

27 + 0.15N = 52

       0.15N = 25

              N = 166.6666666...

Sum moments about N to zero

(Same as saying CW and CCW moments must balance)

190(0.2 + 0.15) + 280(0.05 + 0.15) - R(0.15) - 90(0.3 - 0.15) = 0

R = 726.6666666...

We could verify this by summing vertical forces to zero.

R - 190 - 280 - 166.666666 - 90 = 0

R = 726.6666666...

8 0
2 years ago
A farmers field , which are close to a stream has experienced a lot of runoff. One possible effect of the run off is that the st
Vladimir79 [104]

Answer:

This statement is false.

Explanation:

If  the farmers field is close to the stream, and has experienced a lot of runoff, the runoff will carry chemicals from the farm into the stream, which includes fertilizers among other chemicals. This runoff into the stream will not lead to a decrease in the level of fertilizers in the stream. Therefore, one of the effect of this cannot be a decrease in the level of fertilizers from the field.

6 0
3 years ago
The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast w
romanna [79]

Answer:

Explanation:

You can use that v = v_{o}+gt or v^{2}=v_{o}^{2}+2gh=(25)^{2}+(2)(10)(381)=8245 \rightarrow v \approx 90.8 m/s.

7 0
2 years ago
If Earth had twice the mass it has now, how would the gravitational force between it and the Sun change?
zhenek [66]

Answer:

a)The gravitational force would be twice as much as it is now

Explanation:

If the earth had twice its mass as it is now, the gravitational force between the sun and the earth would be twice as much as it is now.

According to Newton's law of universal gravitation "the gravitational force of attraction between bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them".

       F_{g}   = \frac{G m _{e} m _{s}  }{r^{2} }

G is the universal gravitation constant

m is the mass

r is the distance

let mass of sun  = s

     mass of earth  = e

 new mass of sun  = s

 new mass of sun  = 2e

input variables;

    F  = \frac{Gx e x s}{r^{2} }    ------ i

   F = \frac{G  x s x 2e}{r^{2} }    ------- ii

From the second equation;

      2F  = \frac{Gx e x s}{r^{2} }

      2F  = F

Therefore, the force will double.

7 0
3 years ago
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