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Andrew [12]
2 years ago
5

Calculate the average rate of decomposition of NH4NO2 by the reaction 2NH4O5(aq) --> N2(g) H2O(g) at the following time inter

val. At time 250 s, the concentration of NH4NO2 is 4.12 M. At time 330 s, the concentration of NH4NO2 is 1.48 M
Chemistry
1 answer:
igor_vitrenko [27]2 years ago
6 0

Answer:

r=-0.033\frac{M}{s}

Explanation:

Hello!

In this case, since the average rate of reaction is computed as a change given by:

r=\frac{\Delta [NH_4NO_2 ]}{\Delta t}

In such a way, given the concentrations at the specified times, we plug them in to obtain:

r=\frac{(1.48M-4.12M)}{(330s-250s)}\\\\r=-0.033\frac{M}{s}

Whose negative sign means the concentration decreased due to the decomposition.

Best regards!

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                      CH₄     +    3/2 O₂     ⇒     CO₂    +   2 H₂O

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Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an
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Explanation:

The given data is as follows.

      T = 120^{o}C = (120 + 273.15)K = 393.15 K,  

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So,            x_{1} = 0.5   and   x_{2} = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

               p^{sat}_{1} (393.15 K) = 9.2 bar

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Hence, we will calculate the partial pressure of each component as follows.

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and,           p_{2} = x_{2} \times p^{sat}_{2}

                         = 0.5 \times 10.5 bar

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                      y_{1} = \frac{p_{1}}{p}

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          \frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}

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