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kenny6666 [7]
3 years ago
11

The speed of light in a solid is 1.24 x 108 m/s. Calculate the index of refraction

Physics
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

125

Explanation:

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If a snowboarder’s initial speed is 4 m/s and comes to rest when making it to the upper level. With a slightly greater initial s
Brrunno [24]

(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

<h3>Conservation of mechanical energy</h3>

The effect of height  and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;

ΔK.E = ΔP.E

¹/₂m(v²- u²) = mg(hi - hf)

¹/₂(v²- u²) = g(0 - hf)

v² - u² = -2ghf

v² = u² - 2ghf

where;

  • v is the final velocity at upper level
  • u is the initial velocity
  • hf is final height
  • g is acceleration due to gravity

when u² = 2gh, then v² = 0,

when gravity reduces, u² > 2gh, and v² > 0

Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

<h3>Final speed</h3>

v² = u² - 2ghf

where;

  • u is the initial speed = 5 m/s
  • g is acceleration due to gravity and its less than 9.8 m/s²
  • v is final speed
  • hf is equal height

Since g on Epislon is less than 9.8 m/s² of Earth;

5² - 2ghf > 3 m/s

Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

Learn more about conservation of mechanical energy here: brainly.com/question/6852965

5 0
2 years ago
Which statement accurately describes a sample of water during parts a and c of the heating curve
vivado [14]

Answer:

A and C is about 12 cm away from each other.

Explanation:

5 0
3 years ago
Read 2 more answers
If the mass of a 1.8 g paperclip was able to be completely converted to energy, how much energy would you obtain?
Anton [14]

Answer:

E=1.62\times 10^{14}\ J

Explanation:

Given that,

The mass of the paperclip, m = 1.8 g = 0.0018 kg

We need to find the energy obtained. The relation between mass and energy is given by :

E=mc^2

Where

c is the speed of light

So,

E=0.0018\times (3\times 10^8)^2\\\\E=1.62\times 10^{14}\ J

So, the energy obtained is 1.62\times 10^{14}\ J.

7 0
3 years ago
Choose the correct statement concerning units of power or energy. a. A kilojoule (kJ) is a unit of power. b. A gigawatt (GW) is
sergiy2304 [10]

Answer:

A kilowatt (kW) is a unit of power.

Explanation:

The power of an object is given by :

P=\dfrac{E}{t}

Here,

E is the energy required

t is time

The SI unit of power is Watts and the SI unit of energy is Joule. the commercial unit of energy is kilowatt per hour.    

Option (1) :  A kilojoule (kJ) is a unit of power is incorrect.

Option (2) : A gigawatt (GW) is a unit of energy is incorrect.

Option (3) : A watt (W) is a unit of energy is incorrect.

Option (4) : A kilowatt x hour per year (kWh/yr) is a unit of energy is incorrect.

Option (4) : A kilowatt (kW) is a unit of power is correct.

Hence, the correct option is (d).

3 0
3 years ago
a 0.199 kg snowball moving west makes an inelastic collision with a 2.89 kg box moving 0.523 m/s west. afterward,they move west
kogti [31]

Answer:

The initial velocity of the snowball was 22.21 m/s

Explanation:

Since the collision is inelastic, only momentum is conserved. And since the snowball and the box move together after the collision, they have the same final velocity.

Let m_1 be the mass of the ball, and v_1 be its initial velocity; let m_2 be the mass of the box, and v_2 be its velocity; let v_f be the final velocity after the collision, then according to the law of conservation of momentum:

m_1v_1+m_2v_2=v_f(m_1+m_2).

From this we solve for v_1, the initial velocity of the snowball:

\boxed{v_1=\frac{v_f(m_1+m_2)-m_2v_2}{m_1}}

now we plug in the numerical values m_1=0.199\:kg, m_2=2.89\:kg, v_2=0.523\:m/s, and v_f=1.92\:m/s to get:

v_1=\frac{1.92*(0.199+2.89)-2.89*0.523}{0.199}

\boxed{v_1=22.21\:m/s}

The initial velocity of the snowball is 22.21 m/s.

<em>P.S: we did not take vectors into account because everything is moving in one direction—towards the west.</em>

4 0
3 years ago
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