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babunello [35]
3 years ago
10

Additional law of log​

Mathematics
1 answer:
Levart [38]3 years ago
7 0


Is that all?? Is there a question , answer choices?
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F(x)=8x^2-2x+3<br> g(x)=12x^2+4x-3<br> what is h(x)=f(x)-g(x)?
Trava [24]

Answer: h(x)=-4x^2-6x+6

Step-by-step explanation:

To find the function h(x), you need to subtract the function f(x)=8x^2-2x+3 and the function g(x)=12x^2+4x-3.

h(x)=f(x)-g(x)\\h(x)=8x^2-2x+3-(12x^2+4x-3)

Distribute the negative sign:

h(x)=8x^2-2x+3-12x^2-4x+3

Now you can add the like terms:

h(x)=-4x^2-6x+6

Therefore, you get that the function h(x) is:

 h(x)=-4x^2-6x+6

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Answer:

  13 1/2

Step-by-step explanation:

X-4 1/6 = 9 1/3

Add 4 1/6 to each side

X-4 1/6+ 4 1/6 = 9 1/3 + 4 1/6

x = 9 1/3 + 4 1/6

  = 9 2/6 + 4 1/6

   13 3/6

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3

Step-by-step explanation:

2 + 2 = 4

4 - 1 = 3

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