1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xxMikexx [17]
3 years ago
15

Which sentence in the passage can be used to conclude that Eris is a dwarf planet and not a planet?

Physics
2 answers:
SIZIF [17.4K]3 years ago
6 0

Answer:

It has several other objects in its orbit , though few are as massive as itself.

Explanation:

A celestial body orbiting the sun is considered  a planet when its mass is more than sum of  all other celestial  bodies moving along with it in its orbit round the sun.

Lelu [443]3 years ago
3 0
Eris is slightly more massive than Pluto. However, both of them are smaller than Earth's Moon.
This should conclude that Eris is a dwarf planet.
You might be interested in
You, Archimedes, suspect that the king’s crown is not solid gold but is instead gold-plated lead. To test your theory, you weigh
hjlf

Answer:

a) 16675.75 Kg/m³ b) 77.6%

Explanation:

the weight of the crown = 60 N, density of gold = 19300 Kg/m^3, density of lead = 11340 kg/m^3, density of water = 1000kg/m^3 and acceleration due to gravity = 9.8 m/s^2

upthrust on the crown = weight in air - weight when fully submerged in water = 60 - 56.4 = 3.6 N

mass of water displaced = 3.6 / 9.8  since weight = mass × g

mass of water displaced = 0.367 Kg

density of water = mass / volume

1000 = 0.367 / volume

cross multiply and find volume

volume of the crown = 0.367 / 1000 = 0.000367 m³ since the crown will displace water of equal volume according to Archimedes principle

Let V1 represent the volume of Gold and let V2 represent the volume of lead

Total volume of the crown = V1 + V2

also

density of gold = mass of gold / V1 and density of lead = mass of lead / V2

19300 = mass of gold in the crown / V1 and 11340 = mass of lead in the crown / V2

19300 V1 = mass of gold and 11340 V2 = mass of lead

add the two together

19300 V1 + 11340 V2 = weigth of the crown / 9.8

19300 V1 + 11340 V2 = 6.12 also

V1 + V2 = 0.000367

make V1 subject of the formula in equation 2

V1 = 0.000367 - V2

substitute for V1 in equation 1

19300 (0.000367 - V2) + 11340 V2 = 6.12

open the bracket

7.083 - 19300 V2 + 11340 V2 = 6.12

rearrange the equation

-7960 V2 = 6.12 - 7.083  

-7960 V2 = -0.963

V2 = -0.963 / -7960 = 0.000121 (volume of lead in the crown)

substitute V2 into equation 2

V1 + 0.000121  = 0.000367m³

V1 = 0.000367 - 0.000121 = 0.000246m³ (volume of gold in the crown)

so mass of gold in the crown = 19300 × 0.000246 = 4.748 kg

and mass of lead = 11340 × 0.000121 = 1.372 kg

average density of the crown = (mass of gold + mass of lead) / total volume = 6.12 / 0.000367 = 16675.75 kg/ m³

b) percentage make of gold = mass of gold / total mass × 100 = 77.6 % approx

4 0
3 years ago
A ball having a mass of 200 g is released from rest at a height of 400 mm above a very large fixed metal surface. If the ball re
AysviL [449]

Answer:

0.9

Explanation:

h = 400 mm, h' = 325 mm

Let the coefficient of restitution be e.

h' = e^2 x h

325 = e^2 x 400

e^2 = 0.8125

e = 0.9

5 0
4 years ago
at certain times the demand for electric energy is low and electric energy is used to pump water to a reservoir 45 m above the g
Readme [11.4K]

The mass of water that must be raised is 5.25\cdot 10^7 kg

Explanation:

Since the process is 70% efficiency, the power in output to the turbine can be written as

P_{out} = 0.70 P_{in}

where P_{in} is the power in input.

The power in input can be written as

P_{in} = \frac{W}{t}

where

W is the work done in lifting the water

t = 3 h = 10,800 s is the time elapsed

The work done in lifting the water is given by

W=mgh

where

m is the mass of water

g=9.8 m/s^2 is the acceleration of gravity

h = 45 m is the height at which the water is lifted

Combining the three equations together, we get:

P_{out} = 0.70 \frac{mgh}{t}

Where

P_{out} = 150 MW = 150\cdot 10^6 W

And solving for m, we find:

m=\frac{Pt}{0.70gh}=\frac{(1.50\cdot 10^6)(10800)}{(0.70)(9.8)(45)}=5.25\cdot 10^7 kg

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

3 0
3 years ago
A common pickup for an electric guitar consists of a coil of wire around a small permanent magnet, as described in Figure 25.5.
Orlov [11]
Guitar pickups are tiny coils with magnets inside them and they work via  the principal of electromagnetic inductance. The metal strings vibrate within the magnetic field of the pickup which generates an electrical current. Since nylon is not a metal, it will not cause <span>fluctuations in that magnetic field. Hope this answer helps.</span>
6 0
3 years ago
Chemical energy is stored in food until it is eaten. The energy in food is an example of _______.
777dan777 [17]
Potential energy is the answer
4 0
3 years ago
Other questions:
  • Which is an example of an unintentional injury? A student decides to cut herself. Two people have a domestic dispute that leads
    5·1 answer
  • How does soil, trees, and air might result in a tradeoff
    8·1 answer
  • B. You are approaching a stoplight moving with a velocity of 42.0 m/s. The light turns
    5·2 answers
  • Which term is defined as an investigative process that recognizes that scientific concepts and
    11·1 answer
  • 3 similar things between HIIT,CrossFit y Bodyweight
    14·1 answer
  • Archerfish are tropical fish that hunt by shooting drops of water from their mouths at insects above the waterÂs surface to knoc
    9·2 answers
  • The current in one wire is 5.00<br> a. what is the current in the other wire.
    15·1 answer
  • The chemical equation for the decomposition of potassium chlorate into potassium chloride and oxygen gas is
    13·1 answer
  • Helpppppppppppppppppppp
    13·1 answer
  • Which of these describes Kepler’s third law of orbital motion?(1 point)
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!