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xxMikexx [17]
3 years ago
15

Which sentence in the passage can be used to conclude that Eris is a dwarf planet and not a planet?

Physics
2 answers:
SIZIF [17.4K]3 years ago
6 0

Answer:

It has several other objects in its orbit , though few are as massive as itself.

Explanation:

A celestial body orbiting the sun is considered  a planet when its mass is more than sum of  all other celestial  bodies moving along with it in its orbit round the sun.

Lelu [443]3 years ago
3 0
Eris is slightly more massive than Pluto. However, both of them are smaller than Earth's Moon.
This should conclude that Eris is a dwarf planet.
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. The magnitudes of two forces are measured to be 120 ± 5 N and 60 ± 3 N. Find the sum
Tju [1.3M]

Explanation:

120+60=180

120-60=60

5 0
2 years ago
Describe how to make a position-time graph.
salantis [7]

Answer:

There's a video called Drawing Position vs Time Graphs made by MrDGenova that may help you, it's only three minutes long.

Explanation:

Hope that helps, if not, you could tell me what you don't understand and I could try explaining it in further detail.

3 0
2 years ago
What is the net force (including direction and magnitude) acting on the object on the above left?
Ber [7]

Answer:

Explanation:

the net force on the right left is 25 N and is directed upward

the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero

i hope this will help you

7 0
2 years ago
The equation r (t )=(2t + 4)⋅i + (√ 7 )t⋅ j + 3t ²⋅k the position of a particle in space at time t. Find the angle between the v
velikii [3]

Answer:

\theta = n\pi/2, {\rm where~n~is~an~integer.}

Explanation:

We should first find the velocity and acceleration functions. The velocity function is the derivative of the position function with respect to time, and the acceleration function is the derivative of the velocity function with respect to time.

\vec{v}(t) = \frac{d\vec{r}(t)}{dt} = (2)\^i + (\sqrt{7})\^j + (6t)\^k

Similarly,

\vec{a}(t) = \frac{d\vec{v}(t)}{dt} = (6)\^k

Now, the angle between velocity and acceleration vectors can be found.

The angle between any two vectors can be found by scalar product of them:

\vec{A}.\vec{B} = |\vec{A}|.|\vec{B}|.\cos(\theta)

So,

\vec{v}(t).\vec{a}(t) = |\vec{v}(t)|.|\vec{a}(t)|.\cos(\theta)\\36t = \sqrt{4 + 7 + 36t^2}.6.\cos(\theta)

At time t = 0, this equation becomes

0 = 6\sqrt{11}\cos(\theta)\\\cos(\theta) = 0\\\theta = n\pi/2, {\rm where~n~is~an~integer.}

7 0
3 years ago
A 30 cm scale has one end broken. The mark at the broken end is 2.6 cm. How would you use it to measure the length of your penci
lidiya [134]

Answer:

the mark of the broken end is 2.6 cm so, we use the scale from the next full mark i.e. 3cm

Explanation:

<em>we </em><em>now </em><em>measure</em><em> </em><em>the </em><em>length</em><em> </em><em>of </em><em>the </em><em>pencil</em><em> </em><em>by </em><em>keeping </em><em>the </em><em>3</em><em> </em><em>c</em><em>m</em><em> </em><em>mark </em><em>of </em><em>the </em><em>scale</em><em> </em><em>at </em><em>it's</em><em> </em><em>left </em><em>end.</em>

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<em>(</em><em>i </em><em>i </em><em>)</em><em> </em>place the scale in the contact with object along it's length

(2) Your eyes must be exactly in front of the point where the measurements to be taken.

Hope_it_helps_mga_ka_joiners_mwehehe

6 0
2 years ago
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