The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.
The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)
Plugging everything in, we have h = (0-1225)/(19.6) = 62.5 meters is the maximum height.
Answer:
(4) 8.5 m/s
Explanation:
You add both the meters together and both the seconds together and then divide them both.
Answer:
Chemical you bodily functions while you are jumping
Sound you feet hitting the ground and the jump rope smacking the ground
Mechanical is you jumping up and down and the jump rope spinning a constant direction
Explanation:
First calculate the time by using following equation:<span>
d= (vi+vf)/2 x t </span>
where t = time
vi is the initial velocity = 23 m/s
<span>vf is the final velocity = 0 m/s</span>
and d is the distance covered = 85m
85 = (23 + 0)/2 x t
t = 85/11.5 = 7.39s
Now use this equation to find acceleration:
a= (vf-vi)/t <span>
a = 0 – 23/ 7.39</span>
a = -3.112 m/s²
<span>so, the acceleration is 3.112 m/s</span>²<span>
</span>
Answer:
Option A: 600 kg.m/s westward
Explanation:
The scenario in question here implies a Linear (straight horizontal line) collision.
Usually, when there is a collision between two(2) objects moving opposite to each other like stated above, the object with the higher momentum tends to be more difficult to stop.
The Formula to use here is: P(w) + P(e) = P(total)
where P(w) is the momentum of the first vehicle travelling Westward,
P(e) is the momentum of the second vehicle travelling Eastward and
P(total) is the total amount of momentum after the collision.
Therefore,
1,800 kg.m/s + (-1,200 kg.m/s) = 600 kg.m/s in the westward direction (Our Answer)
Please note that the negative sign in front of (-1,200 kg.m/s) implies that it is moving in a direction opposite to that of the other vehicle.
