The acceleration that the cheeseburger experienced is 20 m/s^2.
Answer:
the value of acceleration as a body moves with an uniform speed is zero
Answer:
112.5 N
Explanation:
50 = GMm/r^2
Let F be the new force of attraction
F/50 = ( G(3M)(3m)/(2r)^2 ) / (GMm/r^2)
[Elimiating G,M,m,r]
F = 112.5 N
Answer:
Rebounce angle is 345°
Rebounce speed is 989.95m/s
Explanation:
Calculate the x component of the velocity of the bullet before impact by using the following relation:
Vbx= Vb Cos thetha
Here, is the initial velocity of the bullet, Vo = 1400m/s and is the incidence angle of the bullet.= theta = 15°
Substituting
Vbx = Cos15 ×1400 = 1352.30m/s
Calculate the y component using the relation:
Vby = Vo Sin theta
Vby = sin 15° × 1400
Vby = 362.35m/s
The rebounce angle = 360 - incidence angle
Rebounce angle =( 360 - 15)° = 345°
The rebound speed V' = Vby - Vbx
V' = (1352.30 - 362.35)m/s
V' = 989.95 m/s
Answer:
true
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