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2 years ago

HELPPP PLEASEEEEE, BRIANLEST WILL BE GIVEN ON CORRECT!

Physics

2 answers:

kicyunya [14]2 years ago

8 0

Answer:

25000 J work with 2500 W power

Explanation:

work done = force . displacement = 500 N . 50 m= 25000 J

Power= work done / time taken = 25000 J / 10 s = 2500 W

myrzilka [38]2 years ago

4 0

Answer:

a. 25000J or 25KJ

b.2500w

Explanation:

a. since we say work is force applied in the same line or straight line

W=F(newtons )*D(metres) 

b. power is work over time 

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2 years ago

CAN ANY OF YALL ANSWER DIS PLS!!!!!!!! I AM GIVING 20 POINTS BTW!!!!!!!

Misha Larkins [42]

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3 years ago

A child is riding a merry-go-round, which has an instantaneous angular speed of 1.25 rad/s and an angular acceleration of 0.745

Elena L [17]

w = instantaneous angular speed = 1.25 rad/s

r = radius = 4.65 m

α = angular acceleration = 0.745 rad/s²

centripetal acceleration is given as

$a_{c}$ = rw²

$a_{c}$ = (4.65 ) (1.25)² = 7.27 m/s²

tangential acceleration is given as

$a_{t}$ = rα

$a_{t}$ =4.65 x 0.745 = 3.46 m/s²

angle is given as

$\theta = tan^{-1}(\frac{a_{c}}{a_{t}})$

$\theta = tan^{-1}(\frac{7.27}{3.46})$

$\theta$ = 64.5 deg

5 0

3 years ago

Another word for a joule per second is a(n)

marishachu [46]

The watt (symbol: W) is the SI derived unit of power, equal to one joule of energy per second

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2 years ago

The range of a projectile depends not only on v0 and θ0 but also on the value g of the free-fall acceleration, which varies from

ElenaW [278]

Answer:

0.0106491902979 m

Explanation:

$v_0$ = Velocity of jump

$\theta_0$ = Angle of jump

g = Acceleration due to gravity

Jump at Berlin

$R_1=\dfrac{v_0sin2\theta_0}{g_1}=8.09\ m$

Jump at Melbourne

$R_2=\dfrac{v_0sin2\theta_0}{g_2}$

The difference is

$\Delta R=R_2-R_1\\\Rightarrow \Delta R=\dfrac{v_0sin2\theta_0}{g_2}-\dfrac{v_0sin2\theta_0}{g_1}\\\Rightarrow \Delta R=v_0sin2\theta_0(\dfrac{1}{g_2}-\dfrac{1}{g_1})\\\Rightarrow \Delta R=v_0sin2\theta_0(\dfrac{1}{g_2}-\dfrac{1}{g_1})\\\Rightarrow \Delta R=\dfrac{v_0sin2\theta_0}{g_1}(\dfrac{g1}{g2}-1)\\\Rightarrow \Delta R=R_1(\dfrac{g1}{g2}-1)\\\Rightarrow \Delta R=8.09(\dfrac{9.8128}{9.7999}-1)\\\Rightarrow \Delta R=0.0106491902979\ m$

The record would have differed by 0.0106491902979 m

5 0

3 years ago

HELPPP PLEASEEEEE, BRIANLEST WILL BE GIVEN ON CORRECT!​

HELPPP PLEASEEEEE, BRIANLEST WILL BE GIVEN ON CORRECT!