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Kipish [7]
3 years ago
7

5.0 km into miles (show work)

Chemistry
1 answer:
Pie3 years ago
7 0

Answer:

5 km = 3.107 miles

one Kilometer is equal to 0.621371 meters

so the equation is

5 km times 0.621371 m

is equal to 3.107

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This is the measure of the quantity of matter
Akimi4 [234]

Answer : Mass

Explanation : Mass measures the amount of matter in a substance or an object.

3 0
3 years ago
Read 2 more answers
If 0.8675 g of KHP requires 24.56 mL of an NaOH solution to reach the equivalence
ValentinkaMS [17]

Answer:

M_{base}=0.173M

Explanation:

Hello there!

In this case, since the titration of acids like KHP with bases like NaOH are performed in a 1:1 mole ratio, it is possible for us to know that their moles are the same at the equivalence point, and the concentration, volume and moles are related as follows:

n_{acid}=M_{base}V_{base}

Thus, by solving for the volume of the base as NaOH, we obtain:

M_{base}=\frac{n_{acid}}{V_{base}} \\\\M_{base}=\frac{0.8675g*\frac{1mol}{204.22g} }{0.02456L} \\\\M_{base}=0.173M

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6 0
3 years ago
magine that an uncharged pith ball is brought into the electrostatic field of a charged rod. The side of the pith ball closest t
ivanzaharov [21]
Answer: option <span>D. be given a positive charge produced by the movement of electrons to the other end of the ball.
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Explanation:


This phenomenon is called electrostatic induction.


The excess of negative charge on the end of the rod will repel the electrons on the side of the pith ball that have been approached to it.

Then the electrons on the pith ball will move far away from this end with it will be left an excess of positive charge.

In this way the rod has induced that the ball acquires a positive charge on one end and a negative charge on the other end.
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4 0
3 years ago
Three Stoichiometry Questions
andrezito [222]

Answer:

Explanation:

7)

Given data:

Mass of aluminium = 2.5 g

Mass of oxygen = 2.5 g

Mass of aluminium oxide = 3.5 g

Percent yield = ?

Solution:

Chemical equation:

4Al + 3O₂   →   2Al₂O₃

Number of moles of Al:

Number of moles = mass/ molar mass

Number of moles = 2.5 g/ 27 g/mol

Number of moles = 0.09 mol

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 2.5 g/ 32 g/mol

Number of moles = 0.08 mol

Now we will compare the moles of aluminium oxide with aluminium and oxygen.

                          Al         ;       Al₂O₃

                           4         :        2

                        0.09      :       2/4×0.09 = 0.045

                          O₂       :        Al₂O₃

                          3         :          2

                         0.08    :        2/3 ×0.08 = 0.053

The number of moles of aluminium oxide produced by Al are less so it will limiting reactant.

Mass of aluminium oxide:

Mass = number of moles × molar mass

Mass = 0.045  × 101.96 g/mol

Mass = 4.6 g

Percent yield:

Percent yield = actual yield / theoretical yield ×100

Percent yield = 3.5 g / 4.6 ×100

Percent yield = 76.1%

8)

Given data:

Mass of copper produced = 3.47 g

Mass of aluminium = 1.87 g

Percent yield = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂(SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/ molar mass

Number of moles = 1.87 g/ 27 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of copper with aluminium.

                          Al         ;       Cu

                           2         :        3

                        0.07      :       3/2×0.09 = 0.105

             

Mass of copper:

Mass = number of moles × molar mass

Mass = 0.105  × 63.55 g/mol

Mass = 6.67 g

Percent yield:

Percent yield = actual yield / theoretical yield ×100

Percent yield =  3.47 g / 6.67 × 100

Percent yield = 52%

                       

4 0
3 years ago
What mass of sodium bicarbonate would be needed to neutralize the spill if a bottle containing 1.75 L of concentrated HCl droppe
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Answer: 4.14g of Na2CO3 would be needed

Explanation:Please see attachment for explanation

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3 years ago
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