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Kipish [7]
3 years ago
7

5.0 km into miles (show work)

Chemistry
1 answer:
Pie3 years ago
7 0

Answer:

5 km = 3.107 miles

one Kilometer is equal to 0.621371 meters

so the equation is

5 km times 0.621371 m

is equal to 3.107

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Mutual

They are balanced steadily which means they’re at the same point
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2 years ago
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Describe what happens when ice changes<br> into liquid water.
chubhunter [2.5K]

Answer:

When ice changes into liquid water it melts. The solidified ice in the frozen, would melt via the burning sun shooting its streaks down at the ice. Which causes the ice to melt, and turn into liquid water.

Explanation:

pp poopoo

3 0
3 years ago
A gas at 1.5 atm had pits ressure decreased to 0.50 atm producing a new volume of 750 ml what was its original volume
Vlada [557]

Answer:

The original volume of the gas is 0.001 mL

Explanation:

This easy excersise can be solved by the law for gases, about pressure and volume; the volume of a gas is inversely proportional to the pressure it exerts.

We can propose the rule by this formula:

P₁  / V₁ = P₂ / V₂

We replace data given: 1.50 atm / V₁ = 0.50 atm / 750 mL

As the rule says, that volume is inversely proportional, and the pressure was decreased, volume must be lower than 750 mL.

1.5atm / (0.5 atm / 750mL) = V₁

V₁ = 0.001 mL

6 0
3 years ago
Calculate the volume 3.00 moles of a gas will occupy at 24.0˚C and 1.003 atm. *
vitfil [10]

Answer: 72.93 litres

Explanation:

Given that:

Volume of gas (V) = ?

Temperature (T) = 24.0°C

Convert 24.0°C to Kelvin by adding 273

(24.0°C + 273 = 297K)

Pressure (P) = 1.003 atm

Number of moles (n) = 3 moles

Molar gas constant (R) is a constant with a value of 0.0821 atm L K-1 mol-1

Then, apply ideal gas equation

pV = nRT

1.003 atm x V = 3.00 moles x 0.0821 atm L K-1 mol-1 x 297K

1.003 atm•V = 73.15 atm•L

Divide both sides by 1.003 atm

1.003 atm•V/1.003 atm = 73.15 atm•L/1.003 atm

V = 72.93 L

Thus, the volume of the gas is 72.93 litres

5 0
3 years ago
PLEASE HELP!<br><br> See picture
Darya [45]

Answer:

See Explanation

Explanation:

The equation of the reaction;

KHSO4(aq) + KOH(aq) -------> K2SO4(aq) + H2O(l)

Number of moles of KHSO4 = 49.6 g/136.169 g/mol = 0.36 moles

Since the reaction is in a mole ratio of 1:1, 0.36 moles of K2SO4 is produced.

Number of moles of KOH = 25.3 g/56.1056 g/mol = 0.45 moles

Since the reaction is 1:1, 0.45 moles of K2SO4 is produced

Hence K2SO4 is the limiting reactant.

Mass of K2SO4 formed = 0.36 moles of K2SO4 * 174.26 g/mol = 62.7 g

So;

1 mole of KHSO4 reacts with 1 mole of KOH

0.36 moles of KHSO4 reacts with 0.36 * 1/1 = 0.36 moles of KOH

Amount of excess KOH = 0.45 moles - 0.36 moles = 0.09 moles

Mass of excess KOH = 0.09 moles * 56.1056 g/mol  = 5 g of excess KOH

5 0
3 years ago
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