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Kipish [7]
3 years ago
7

5.0 km into miles (show work)

Chemistry
1 answer:
Pie3 years ago
7 0

Answer:

5 km = 3.107 miles

one Kilometer is equal to 0.621371 meters

so the equation is

5 km times 0.621371 m

is equal to 3.107

You might be interested in
How many atoms are here in the following?
Elina [12.6K]

Answer:

A. 6N

B. 4H, 2O

C. 4H, 4N, 12O

D. 2Ca, 4O, 4H

E. 3Ba, 6Cl, 18O

F. 5Fe, 10N, 30O

G. 12Mg, 8P, 32O

H. 4N, 16H, 2S, 8O

I. 12Al, 18Se, 72O

J. 12C, 32H

I am 90% sure this is correct

6 0
3 years ago
Calculate the volume of 0.10 g of titanium (4.51 g/cm³).
Juli2301 [7.4K]

The volume of titanium with mass of 0. 10g and density of 4. 51 g/cm³ is 0. 02 cm³

<h3>What is volume?</h3>

Volume is known to be equal to the mass divided by the density.

It is written thus:

Volume = Mass / density

<h3>How to calculate the volume</h3>

The volume is calculated using the formula:

Volume = mass ÷ density

Given the mass = 0. 10g

Density = 4.51 g/cm³

Substitute the values into the formula

Volume of titanium = 0. 10 ÷ 4.51 = 0. 02 cm³

Thus, the volume of titanium with mass of 0. 10g and density of 4. 51 g/cm³ is 0. 02 cm³

Learn more about volume here:

brainly.com/question/1762479

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4 0
2 years ago
Determine the mass in grams of 4.69 x 1021 atoms of barium. (The
Virty [35]

Answer:

1.07 g Ba

Explanation:

Hello there!

In this case, according to the definition of the Avogadro's number and the molar mass, it is possible to say that 6.022x10^{23} atoms of barium equal one mole, and at the same time, 1 mole equals 137.327 grams of this element; thus, it is possible to say that 6.022x10^{23} atoms of barium have a mass of 137.327 grams; therefore, it i possible for us to calculate the required mass in grams as shown below:

4.69x10^{21}atoms*\frac{137.327gBa}{6.022x10^{23} atoms} \\\\=1.07gBa

Best regards!

5 0
3 years ago
Erbium (Er) is element 68 on the periodic table. A sample contains 5.04×1023 atoms of Er. Calculate the amount of Er.
Korvikt [17]

Answer:

139.98 g to nearest hundredth.

Explanation:

Using Avogadro's Number:

One mole (167.26 g) of Erbium  equates to  6.022141 * 10^23 atoms.

So 5.04 * 10^23 = 167.26 * 5.04/6.022141

= 139,98 g.

3 0
3 years ago
Write a balanced equation for the double-replacement precipitation reaction described, using the smallest possible integer coeff
ahrayia [7]

Answer:

NH4Br + AgNO3 —> AgBr + NH4NO3

Explanation:

When ammonium bromide and silver(I) nitrate react, the following are obtained as shown below:

NH4Br(aq) + AgNO3(aq) —>

In solution, NH4Br(aq) and AgNO3(aq) will dissociate as follow:

NH4Br(aq) —> NH4+(aq) + Br-(aq)

AgNO3(aq) —> Ag+(aq) + NO3-(aq)

The double displacement reaction will occur as follow:

NH4+(aq) + Br-(aq) + Ag+(aq) + NO3-(aq) —> Ag+(aq) + Br-(aq) + NH4+(aq) + NO3-(aq)

NH4Br(aq) + AgNO3(aq) —> AgBr(s) + NH4NO3(aq)

6 0
4 years ago
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