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s344n2d4d5 [400]
3 years ago
12

I neeeeeeeeed help you within 30 min

Chemistry
1 answer:
sladkih [1.3K]3 years ago
8 0

Answer:

The answers to your question are given below

Explanation:

The equation for the reaction is given below:

2KClO₃ —> 2KCl + 3O₂

The total number of each atoms present in the reactants and products can be obtained by doing a head count as illustrated below:

Reactants >>>>>> Number of atoms

Potassium (K) >>> 2 × 1 = 2

Chlorine (Cl) >>>> 2 × 1 = 2

Oxygen (O) >>>>> 2 × 3 = 6

Products >>>>>>> Number of atoms

Potassium (K) >>> 2 × 1 = 2

Chlorine (Cl) >>>> 2 × 1 = 2

Oxygen (O) >>>>> 3 × 2 = 6

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How many grams of H2SO4 are needed to prepare 500. mL of a .250M solution?
zavuch27 [327]

Answer:

We need 12.26 grams H2SO4

Explanation:

Step 1: Data given

Volume of a H2SO4 solution = 500 mL = 0.500 L

Concentration of the H2SO4 solution = 0.250 M

Molar mass of H2SO4 = 98.08 g/mol

Step 2: Calculate moles H2SO4

Moles H2SO4 = concentration * volume

Moles H2SO4 = 0.250 M * 0.500 L

Moles H2SO4 = 0.125 moles

Step 3: Calculate mass of H2SO4

Mass of H2SO4 = moles * molar mass

Mass of H2SO4 = 0.125 moles * 98.08 g/mol

Mass of H2SO4 = 12.26 grams

We need 12.26 grams H2SO4

7 0
3 years ago
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