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Salsk061 [2.6K]
3 years ago
11

What function do mirrors serve in reflecting telescopes????

Chemistry
1 answer:
UkoKoshka [18]3 years ago
4 0
Enlarge image i think
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Calculate the ph of a 0.17 m solution of c6h5nh3no3 (kb for c6h5nh2 = 3.8 x 10-10). record your ph value to 2 decimal places.
MatroZZZ [7]
<span>Mass of the solution = 0.17m
 Kb for C6H5NH2 = 3.8 x 10^-10
 We know Ka for C6H5NH2 = 1.78x10^-11
  We have Kw = Ka x Kb => Ka = Kw / Kb
  => (C2H5NH2)(H3O^+)/(C2H5NH3^+) => 1.78x10^-11 = K^2 / 0.17
 K^2 = 3 x 10^-12 => K = 1.73 x 10^-6.
 pH = -log(Kw(H3O^+)) = -log(1.73 x 10^-6) = 5.76</span>
6 0
3 years ago
Which substance can not be broken down by a chemical change
tangare [24]
Well, an element is a substance that cannot be decomposed into a simpler substance by chemical change, so element is the answer you are probably looking for! Hope this helps!
7 0
3 years ago
PLEASE HELP!!!!!!!!! WILL MARK BRAINLIEST
frozen [14]

Answer:

19.278049929737628457607385688801

Explanation:

Volume = L * W * H

Volume = 17.78 * 9.21 * 4.45 = 728.70441

Density = Mass / Volume

Mass = 14,048

14,048 / 728.70441 = 19.278049929737628457607385688801

Density = 19.278049929737628457607385688801

7 0
3 years ago
Read 2 more answers
A spectral line has a wavelength of 7.35 *10-7 m. What is the energy of this radiation?
antoniya [11.8K]

Answer:

2.7 x 10^-19 J

Explanation:

The formula needed for this problem is

E = hν

where E = energy, h = Planck's constant = 6.626x10^-34 and ν is the frequency

c = λν

where c = speed of light = 3x10^8, and λ = wavelength

3x10^8 = 7.35x10^-7 . ν

ν = 4.08 x 10^14 Hz

E = 6.626x10^-34 . 4.08x10^14 = 2.7 x 10^-19 J

8 0
3 years ago
A piece of copper absorbs 5000 J of energy and undergoes a temperature change from 100 °C to 200 °C. What is the mass of the pie
irakobra [83]

Answer:

B.) 129.9 grams

Explanation:

To find the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

The specific heat of copper is 0.385 J/g°C. Knowing this, you can plug the given values into the equation and simplify to isolate "m".

Q = mcΔT                                                            <----- Equation

5000 J = m(0.385 J/g°C)(200 °C - 100 °C)        <----- Insert values

5000 J = m(0.385 J/g°C)(100)                            <----- Subtract

5000 J = m(38.5)                                                <----- Multiply 0.385 and 100

129.9 = m                                                             <----- Divide both sides by 38.5

8 0
1 year ago
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