Ionic compound is the answer
They're never the same ray.
Explanation:
Given that,
The force exerted by the stick on the puck is 975 N
The stick is in contact with the puck for 0.0049 s
Initial speed of the puck, u = 0 (at rest)
(a) We need to find the impulse imparted by the stick to the puck.
Impulse = Force × time
J = 4.7775 kg-m/s
(b) Mass of the puck, m = 1.76 kg
We need to find the speed of the puck just after it leaves the hockey stick.
Let the speed be v.
As impulse is equal to the change in momentum.

So, when the puck leaves the hockey stick its speed is 2.86 m/s.
I think the correct answer from the choices listed above is the first option. The statement that best accounts for these different opinions would be that <span>scientists propose contradictory ideas to include all possibilities. Hope this answers the question. Have a nice day.</span>
Answer:
The initial speed of the ball is 3.93 m/s.
Explanation:
It is given that,
A ball is thrown horizontally from a height of 19 m, h = 19 m
Let u is the initial speed of the ball so, its final velocity, v = 5u
Using third equation of motion as :



u = 3.93 m/s
So, the initial speed of the ball is 3.93 m/s. Hence, this is the required solution.