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3 years ago

15

How would the gravitational force between the earth and the moon change if the moon had half the mass?

1 answer:

Vikki [24]3 years ago

5 0

The moon's gravity, combined with the waltz of Earth and the moon around their center of mass, forces the oceans into an oval shape, with two simultaneous high tides. ... If the moon were half its mass, then the ocean tides would have been correspondingly smaller and imparted less energy to it.

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The quality of ____ opposes the flow of electric current through a material .

QveST [7]

The answer is Resistance

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3 years ago

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An open diving chamber rests on the ocean floor at a water depth of 60 meter. Find the air pressure (gage pressure relative to t

Fofino [41]

Answer:

Gauge Pressure required = 606.258 kPa

Explanation:

Water will not enter the chamber if the pressure of air in it equals that of the water which tries to enter it.

Thus at a depth of 60m we have pressure of water equals

$P(z)=P_{0}+\rho _wgh$

Now the gauge pressure is given by

$P(z)-P_{0}=\rho _wgh$

Applying values we get

$P(z)-P_{0}=\rho _wgh\\\\P_{gauge}=1.03\times 1000\times 9.81\times 60Pa\\\\P_{gauge}=606258Pascals\\\\P_{gauge}=606.258kPa$

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4 years ago

Dr. Eriksson is working on a material called selenium. She is adding a certain number and type of atoms to the selenium, which w

Katarina [22]

Answer:

Selenium is a semiconductor

Explanation:

Selenium is a semiconductor.

Elements in the column IV and VI of the periodic table are referred to as Semiconductor.

Selenium lies in the column VI along with Tellurium

Some other elements of the column IV are silicon, germanium, and tin

4 0

3 years ago

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If a 375 watt heater has a current of 5.0 A, what is the resistance of the heating element?

liberstina [14]

P=IV
V=IR

P=I(IR)
P=I²R
375=5²R
R=375/25
R=15

7 0

4 years ago

An ore car of mass 39000 kg starts from rest and rolls downhill on tracks from a mine. At the end of the tracks, 25 m lower vert

Musya8 [376]

Answer:

x = 5.79 m

Explanation:

given,

mass of the car = 39000 Kg

spring constant = 5.7 x 10⁵ N/m

acceleration due to gravity = 9.8 m/s²

height of the track = 25 m

length of spring compressed = ?

using conservation of energy

potential energy is converted into spring energy

$m g h = \dfrac{1}{2}kx^2$

$x =\sqrt{\dfrac{2 m g h}{k}}$

$x =\sqrt{\dfrac{2\times 39000 \times 9.8 \times 25}{5.7 \times 10^{5}}}$

$x =\sqrt{33.5263}$

x = 5.79 m

the spring is compressed to x = 5.79 m to stop the car.

3 0

3 years ago