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polet [3.4K]
3 years ago
15

How would the gravitational force between the earth and the moon change if the moon had half the mass?

Physics
1 answer:
Vikki [24]3 years ago
5 0

The moon's gravity, combined with the waltz of Earth and the moon around their center of mass, forces the oceans into an oval shape, with two simultaneous high tides. ... If the moon were half its mass, then the ocean tides would have been correspondingly smaller and imparted less energy to it.

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A car drives to the east in a time of 6 hours. Then, immediately (not realistic, but just assume this is the case for this probl
garri49 [273]

Answer:

Average speed of car in the first trip is 10 km/hr    

Explanation:

It is given that first the car drives 6 hours to the east

Then travels 12 km to west in 3 hours

Average speed for the entire trip = 8 km/hr

Total time = 3+6 = 9 hour

So distance traveled in 9 hour = 9×8 = 72 km

As the car travel 12 km in west so distance traveled in east = 72-12 = 60 km

Time by which car traveled in east = 6 hour

So speed =\frac{distance}{time}=\frac{60}{6}=10km/hr

So average speed of car in the first trip is 10 km/hr

7 0
4 years ago
A student project is required to be portable and hand held. It requires 6 V DC power at a current of 150 mA. The batteries for t
egoroff_w [7]

Answer:

a. 5 batteries b. 1050 mAh

Explanation:

Here is the complete question

A student project is required to be portable and hand held. It requires 6 V DC power at a current of 150 mA. The batteries for the power supply must last for a minimum of 7 hours of continuous operation. NiMH rechargeable batteries in AA size are to be used. A) How many batteries are needed? B) What mAh capacity should the batteries have?

Solution

A) How many batteries are needed?

Since the nominal voltage for a single NiMH battery is 1.2 V per battery and we require 6V DC power, we combine the batteries in series to obtain a total voltage of 6 V. The number of batteries required, n = total voltage/voltage per cell = 6V/1.2V per battery = 5 batteries

So, the number of batteries needed is 5.

B) What mAh capacity should the batteries have?

Since the batteries are in series, they would each deliver a current of 150 mA. Since we require a current of 150 mA for 7 hours, the number of milliampere-hours capacity mAh of batteries required is Q = It where I = current = 150 mA and t = time = 7 hours.

So, Q = It = 150 mA × 7 h = 1050 mAh.

So, the batteries should have a mAh of 1050 mAh

4 0
4 years ago
During a lie detector test, a voltage of 6V is impressed across two fingers. When a certain question is asked, the resistance be
sdas [7]

The current initially through the fingers is : 1.5 * 10⁻⁵ amp

The current when the resistance between them drops is : 3 * 10⁻⁵ amp

<u>Given data : </u>

Voltage ( V ) = 6 V

Initial resistance ( r ) = 400,000 ohms

Final resistance ( R ) = 200,000 ohms

<h3>Determine The Current </h3>

A) initially through fingers

I = V / r

 = 6 V / 400,000

 = 1.5 * 10⁻⁵ amp

B) when the resistance between them drops

I = V / R

 = 6 V / 200000

 = 3 * 10⁻⁵ amp

Hence we can conclude that The current initially through the fingers is : 1.5 * 10⁻⁵ amp and The current when the resistance between them drops is : 3 * 10⁻⁵ amp

Learn more about current calculation : brainly.com/question/25922783

6 0
2 years ago
A 6.89-nC charge is located 1.76 m from a 4.10-nC point charge. (a) Find the magnitude of the electrostatic force that one charg
iogann1982 [59]

Answer: a) 8.2 * 10^-8 N or 82 nN and b) is repulsive

Explanation: To solve this problem we have to use the Coulomb force for two point charged, it is given by:

F=\frac{k*q1*q2}{d^{2}}

Replacing the dat we obtain F=82 nN.

The force is repulsive because the points charged have the same sign.

5 0
3 years ago
A NASCAR driver weighing 75 kg enters a corner with a radius of 155 meters. If his acceleration is 100 m/s2. What is tangential
Ymorist [56]

The tangential velocity of the car is 124.5 m/s

Explanation:

The centripetal acceleration of an object in uniform circular motion is given by:

a=\frac{v^2}{r}

where

a is the acceleration

v is the tangential velocity

r is the radius of the circle

For the car in this problem, we have:

a=100 m/s^2 is the centripetal acceleration

r = 155 m is the radius of the turn

Solving for v, we find the tangential velocity of the car:

v=\sqrt{ar}=\sqrt{(100)(155)}=124.5 m/s

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

3 0
3 years ago
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