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masha68 [24]
3 years ago
10

What is the density (in grams per milliliter) of the rectangular bar if it has a mass of 186.77 g and measures 4.26 cm in length

, 1.42 cm in width, and 19.21 cm in height
Chemistry
1 answer:
Alinara [238K]3 years ago
8 0

Answer:

roh = 1.6x10^{-3}

Explanation:

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Answer:

Carbon moves from the atmosphere to plants. ...

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Carbon moves from living things to the atmosphere. ...

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Carbon moves from the atmosphere to the oceans.

Explanation:

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3 years ago
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What is the elevation of hachure line A?<br><br> 125 feet<br> 75 feet<br> 100 feet<br> 50 feet
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<span> elevation between index contours would be </span><span>125 feet</span>
7 0
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If He gas has an average kinetic energy of 4310 J/mol under certain conditions, what is the root mean square speed of O2 gas mol
Free_Kalibri [48]

Answer:

The root mean square speed of O2 gas molecules is

<u>519.01 m/s</u>

<u></u>

Explanation:

The root mean square velocity  :

v_{rms}=\sqrt{\frac{3RT}{M}}

K.E_{avg}=\frac{3}{2}RT

K.E =\frac{1}{2}mv_{rms}^{2}

Molar mass , M

For He = 4 g/mol

For O2 = 2 x 16 = 32 g/mol

O2 = 32/1000 = 0.032 Kg/mol

First calculate the temperature at which the K.E of He is 4310J/mol

K.E of He =

K.E_{avg}=\frac{3}{2}RT

T=\frac{2(K.E)}{3(R)}

K.E of He = 4310 J/mol

T=\frac{2(4310J/mol)}{3(8.314J/Kmol)}

T=345.60K

<u>Now , Use Vrms to calculate the velocity of O2</u>

v_{rms}=\sqrt{\frac{3(8.314J/Kmol)(345.60K)}{0.032Kg/mol}}

v_{rms}=\sqrt{\frac{8619.9552}{0.032}}

v_{rms}=\sqrt{26935.001}

v_{rms}=519.01m/s

6 0
4 years ago
Which element would likely have the lowest electronegativity value?
Sindrei [870]
Is it multiple choice or direct?
4 0
3 years ago
One way to account for the mass "lost" in a reaction that involves a gas would be to________.
sergiy2304 [10]

Answer:

Place the experiments on a scale

Explanation:

If you place two of the same experiments on a scale, and cover one with a cup, the one with the cup will "lose" mass, while the other won't, due to the cup being a "containment field" I guess you could call it.

5 0
3 years ago
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