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Luden [163]
3 years ago
5

What adaptation of vines help them grow on other plants in order to get more sunlight?

Chemistry
2 answers:
Nadya [2.5K]3 years ago
8 0
Yes that is correct
riadik2000 [5.3K]3 years ago
6 0
A. Flexible stems

This helps vines bend and stretch to reach higher on the tree or rock
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This is the process that cells reproduce and replace old or damaged cells.
Vedmedyk [2.9K]

Answer:

mitosis

Explanation:

because ur a cumt who doesn't know the answer

8 0
3 years ago
Calculate the molar solubility of copper(II) arsenate (Cu3(AsO4)2) in water. Use 7.6 x 10^-36 as the solubility product constant
Molodets [167]
Molar solubility<span> is the number of moles of a substance (the solute) that can be dissolved per liter of solution before the solution becomes saturated. We calculate as follows:

</span>3Cu2+ + 2(AsO4)3-<span> = Cu3(AsO4)2
</span>
7.6 x 10^-36 = (3x^3)(2x^2)
x = 6.62 x 10^-8 M
8 0
3 years ago
Read 2 more answers
A student is doing online research. The student's teacher said that some
adoni [48]
Websites that end in .com or .org should be avoided.
3 0
3 years ago
A 1.42-g sample of a pure compound with formula m2so4 was dissolved in water and treated with an ex- cess of aqueous calcium chl
solong [7]

The reaction between m_{2}SO_{4} with calcium chloride can be shown as-m_{2}SO_{4}+CaCl_{2}→CaSO_{4}↓+2mCl. The molecular weight of CaSO_{4} is 136.14g. The weight of sulfate ion is 96.06g. The molecular weight of m_{2}SO_{4} = (2×m + 96.06). From the reaction we can see that 1 mole of calcium chloride reacts with 1 molesm_{2}SO_{4} to produce 1 mole of calcium sulfate. Now 1.36g of calcium sulfate is equivalent to 1.36/136.14=9.989×10^{-3} moles of calcium sulfate.

Thus, 9.989×10^{-3} moles of m_{2}SO_{4} reacts in this reaction.

Let assume the atomic mass of m is x thus the molecular weight of m_{2}SO_{4} is 2x+96.

So we may write 9.989×10^{-3}× (2x+96) =1.42

Or, 2x + 96 = 142.146

Or, 2x = 46.146

Or, x = 23.073

Thus the atomic mass of m is 23.073. The atom (m) is sodium (Na).  

8 0
3 years ago
At equilibrium the reactant and product concentrations are constant because a change in one direction is balanced by a change in
Anna [14]

Answer: a. The concentrations of the reactants and products have reached constant values

Explanation:

The reactions which do not go on completion and in which the reactant forms product and the products goes back to the reactants simultaneously are known as equilibrium reactions.  For a chemical equilibrium reaction, equilibrium state is achieved when the rate of forward reaction becomes equal to rate of the backward reaction.

Equilibrium state is the state when reactants and products are present but the concentrations does not change with time and are constant.

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For a equilibrium reaction,

A\rightleftharpoons B

K_{eq}=\frac{[B]}{[A]}

Thus the correct answer is the concentrations of the reactants and products have reached constant values.

5 0
3 years ago
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