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Romashka [77]
2 years ago
8

A car accelerates at a rate of 13m/s^2[S]. If the car's initial velocity is 120km/h[N]. What will be its final velocity in m/s,

after 2 seconds.
Physics
1 answer:
balu736 [363]2 years ago
4 0

Answer:

the final velocity of the car is 59.33 m/s [N]

Explanation:

Given;

acceleration of the car, a = 13 m/s²

initial velocity of the car, u = 120 km/h = 33.33 m/s

duration of the car motion, t = 2 s

The final velocity of the car in the same direction is calculated as follows;

v = u + at

where;

v is the final velocity of the car

v = 33.33 + 13 x 2

v = 59.33 m/s [N]

Therefore, the final velocity of the car is 59.33 m/s [N]

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A5 cm object is 18.0 cm from a convex lens, which has a focal length of 10.0 cm.
Masja [62]

Explanation:

We have,

Height of object is 5 cm

Object distance from a convex lens is 18 cm

Focal length of convex lens is 10 cm

i.e. h = 5 cm

u = -18 cm

f = +10 cm

Let v is distance of the image from the lens. Using lens formula :

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{(-18)}\\\\v=22.5\ cm

The magnification of lens is :

m=\dfrac{v}{u}=\dfrac{h'}{h}, h' is height of the image

\dfrac{v}{u}=\dfrac{h'}{h}\\\\h'=\dfrac{vh}{u}\\\\h'=\dfrac{22.5\times 4}{(-18)}\\\\h'=-5\ cm

h' = -5.00 cm (in three significant figures)

6 0
3 years ago
If 500 J of energy were added to 1 kg of each of these samples , which would experience the LEAST temperature increase
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There's no way we can begin to make a choice if we don't know WHAT the samples are samples OF.

I CAN give you some info, however, that will probably help you make the right choice from the hidden list that you have.

If water is on the list, then that's the answer, EXCEPT if liquid ammonia is on the list.  Liquid ammonia is the only known substance on Earth that beats water as the answer to this question.

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Fast-moving glaciers that can move up to 6 kilometers per year
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Air exits a turbine at 200 kPa and 1508C with a volumetric flow rate of 7000 liters/s. Modeling air as an ideal gas, determine t
liraira [26]

Answer:

mass flow rate = 11.464 kg/sec

Explanation:

given data

P = 200 kPa = 2 × 10^{5}  Pa

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solution

first we get here molar flow rate that is express as

molar flow rate  = \frac{Pv}{RT}   .................1

put here value

molar flow rate  = \frac{2 \times 10^5 \times 7}{8.314\times 423}  

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and

now we get mass flow rate

mass flow rate = molar flow rate × average  mol weight ..............2

mass flow rate = 398.06 × 28.8

mass flow rate = 11464.3 g/sec

mass flow rate = 11.464 kg/sec

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