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-BARSIC- [3]
3 years ago
13

A runner accelerated to 4 m/s^2 for 20 seconds before winning the race.How far did he/she run?

Physics
1 answer:
creativ13 [48]3 years ago
8 0

Answer:

s=800 m

Explanation:

Given that,

Acceleration of a runner, a = 4 m/s²

Time, t = 20 seconds

We need to find the distance covered by her. Initially, she was at rest. It means its initial velocity is equal to 0. So, using second equation of motion as follows :

s=ut+\dfrac{1}{2}at^2

Herre, u = 0

s=\dfrac{1}{2}at^2\\\\s=\dfrac{1}{2}\times 4\times (20)^2\\\\s=800\ m

So, she will cover a distance of 800 m.

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here we will use the momentum conservation

initial total momentum = final total momentum

P_i = P_f

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

now plug in all data here

m(0) + 50m(8.1) = mv + 50mv

405 = 51 v

v = 7.94 m/s

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