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2 years ago

When vectors are added or subtracted, the net force is called the _____.

Physics

2 answers:

dalvyx [7]2 years ago

7 0

Answer:

It's called the resultant

natita [175]2 years ago

4 0

Answer:

Option (3)

Explanation:

The resultant vector is usually defined as a single vector that is obtained from the addition or the subtraction of two distinct vectors. It is widely used in the field of Mathematics and Physics, where this resultant vector denotes the magnitude as well as direction of any physical property such as velocity, force, and are represented graphically.

These resultant vectors along with the other vectors are drawn by using an arrow.

Thus, the correct answer is option (3).

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Find the acceleration of a car with the mass of 1,200 kg and a force of

Mashutka [201]

Answer:9.17 m/s^2

Explanation:

mass=1200kg

Force=11 x 10^3 N

Acceleration=force ➗ mass

Acceleration=11 x 10^3 ➗ 1200

Acceleration=9.17

Acceleration=9.17 m/s^2

3 0

2 years ago

If a cannon is fired use a=F/m to explain what happens to the cannon and the cannonball.

Serga [27]

Im not really sure about this im stuck to

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3 years ago

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The atmosphere of Neptune and Uranus have a blue color because of which gas?

kirza4 [7]

They are blue because of hydrogen helium and methane

5 0

3 years ago

What phenomenon causes colors of visible light to be separated by a prism?

Allushta [10]

Dispersion im pretty sure

6 0

2 years ago

Desperado, a roller coaster built in Nevada, has a mass of 800 kg. It also has a vertical drop of 225 feet down the first hill.

weeeeeb [17]

Answer:

the work done by friction on the car is 524,582 J.

Explanation:

Given;

mass of the roller coaster, m = 800 kg

distance moved by the coaster, d = 225 ft = 68.58 m

final velocity of the coaster, v = 80 mi/h = 35.76 m/s

The time taken for the coaster to drop down the hill is calculated as;

$t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\ \times \ 68.58}{9.8} } \\\\t = 3.74 \ s$

The work done by friction on the car is calculated as;

$W =F\ \times \ d = \frac{mv}{t} \times \ d\\\\W = \frac{800 \ \times \ 35.76 }{3.74} \times \ 68.58\\\\W = 524,582 \ J$

Therefore, the work done by friction on the car is 524,582 J.

6 0

3 years ago