Answer:
Part a)

Part b)

Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass
Explanation:
Part a)
Let say the collision between Moose and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part b)
Let say the collision between Camel and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass
Answer:
Ea = 112500[J]
Eb = 87500[J]
Explanation:
To solve this problem we must use the principle of energy conservation which tells us that the energy of a body plus the work done or applied by the body equals the final energy of a body.
This can be easily visualized by the following equation:

Now we must define the energies at points A & B.
<u>For point A</u>
At point A we only have kinetic energy since it moves at 15 [m/s]
So the kinetic energy
![E_{A}=\frac{1}{2}*m*v_{A}^{2} \\E_{A}=\frac{1}{2} *1000*(15)^{2} \\E_{A}=112500[J]](https://tex.z-dn.net/?f=E_%7BA%7D%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2Av_%7BA%7D%5E%7B2%7D%20%20%5C%5CE_%7BA%7D%3D%5Cfrac%7B1%7D%7B2%7D%20%2A1000%2A%2815%29%5E%7B2%7D%20%5C%5CE_%7BA%7D%3D112500%5BJ%5D)
The final kinetic energy can be calculated as follows:
![112500-25000=E_{B}\\E_{B}=87500[J]](https://tex.z-dn.net/?f=112500-25000%3DE_%7BB%7D%5C%5CE_%7BB%7D%3D87500%5BJ%5D)
A- additive colors
Because if colors are added it gets brighter but if colors are subtracted it makes black
Answer:
It is half the field strength at 0.5cm
Explanation: