Answer:
mass HF = 150.05 g
Explanation:
- SiO2(s) + 4HF(g) → SiF4(g) + 2H2O(l)
⇒ Q = (ΔH°rxn * mHF) / (mol HF * MwHF )
∴ MwHF = 20.0063 g/mol
∴ mol HF = 4 mol
∴ ΔH°rxn = - 184 KJ
∴ Q = 345 KJ
mass HF ( mHF ):
⇒ mHF = ( Q * mol HF * MwHF ) / ΔH°rxn
⇒ mHF = ( 345 KJ * 4mol HF * 20.0063 g/mol ) / 184 KJ
⇒ mHF = 150.05 g HF
Answer:
<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.
Explanation:
The balanced equation:
1 mole Na3PO4 = 164 g/mole (Molar mass)
1 mole NaOH = 40 g/mole (Molar mass)
Now,
1 mole of Na3PO4 produce = 3 mole of NaOH
164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH
or
120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4
1 g/mol of NaOH is produced from =
100 grams of NaOH is produced from =
gram of Na3PO4
calculate,
= 136.67 g
Answer:
C) 3.3 x 104 grams
Explanation:
1 mole of water contains 6.02 × 10^23 atoms
1.1 × 10^27 atoms will contain;
1.1 × 10^27 ÷ 6.02 × 10^23
= 0.1827 × 10^( 27 - 23)
= 0.1827 × 10^(4)
= 1.827 × 10³ moles of water.
To convert mole to mass in grams, we use the formula;
mole (n) = mass (m) ÷ molar mass (MM)
Molar mas of water (H2O) = 1(2) of H + 16 of O = 18g/mol
mole = mass/molar mass
1.827 × 10³ = mass / 18
mass = 1.827 × 10³ × 18
mass = 32.886 × 10³
mass = 3.286 × 10⁴
mass = 3.3 × 10⁴ grams
