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iVinArrow [24]
3 years ago
9

Explain the difference between an ignition transformer and a solid-state igniter

Chemistry
1 answer:
bazaltina [42]3 years ago
3 0

Ignition transformer

1.      Weight of the transformer is more.

2.      Voltage output of the transformer is from 10,000 volts to 14,000 volts.

3.      Due to lower voltage output, fuel vaporization and ignition will be slow.

4.      When there is a drop in voltage supply, the transformer gets affected.

5.      Consumption of electricity is more.

 

Solid state igniter.

1.      Igniter weighs very light

2.      Igniter giver voltage output in the range of 14,000 volts to 20,000 volts

3.      Higher voltage output leads to faster vaporization of fuel and ignition

4.      Very small affect is observed when there is a voltage drop.

5.      Less electricity is consumed.

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Stannum has a body centered tetragonal with lattice constant, a = b = 5.83A and c = 3.18A. If the atomic radius is 0.145 nm, det
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Answer:

the atomic packing factor of Sn is 0.24

Explanation:

a = b = 5.83A and c = 3.18A.

Volume of unit cell = a²c

= (5.83)² *  3.18 * 10⁻²⁴ cm³

= 1.08 * 10⁻²²cm³

Volume of atoms =

2 \times  \frac{4}{3} \pi r^3

(∴ BCC, effective number of atom is 2)

Volume of atoms =

2 * \frac{4}{3} *3.14*(0.145*10^-^7cm)^3

= 2.55*10⁻²³cm³

\text {Atomic packing factor}=\frac{\text {volume occupied by atom}}{\text {volume of unit cell }}

=\frac{2.55*10^-^2^3}{1.08*10^-^2^2} \\\\=0.24

<h3>therefore, the atomic packing factor of Sn is 0.24</h3>
4 0
4 years ago
A balloon filled with 1.22 L of gas at 286 K is heated until the
TiliK225 [7]

Answer: 670K

Explanation:

Given that,

Original volume of gas V1 = 1.22 L

Original temperature T1 = 286 K

New volume V2 = 2.86 L

New temperature T2 = ?

Since volume and temperature are involved while pressure is constant, apply the formula for Charles law

V1/T1 = V2/T2

1.22 L/286 K = 2.86 L/ T2

Cross multiply

1.22 L x T2 = 286 K x 2.86 L

1.22T2 = 817.96

Divide both sides by 1.22

1.22T2/1.22 = 817.96/1.22

T2 = 670.459 K (Round to the nearest whole number as 670 K)

Thus, the temperature of the gas is 670 Kelvin

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