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Paladinen [302]
3 years ago
12

Why does a scientist form a hypothesis?

Chemistry
1 answer:
Kryger [21]3 years ago
8 0
Answer: B (to provide a statement that can be tested with an experiment
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How many neutrons are in Cesium-130 (130/50 Cs)
Sergeeva-Olga [200]
 Best Answer:<span>  </span><span>Cross sections for formation of cesium and rubidium isotopes produced by bombardment of uranium with protons ranging in energy from 0.1 to 6.2 Bev were measured both radiochemically and mass spectrometrically. Independent yields were determined for Rb/sup 84/, Rb/sup 86/, Cs/sup 127/, Sc, su p 129/. Cs/sup 130/, Cs/sup 131/, Cs/sup 132/, Cs/sup 134/, Cs/sup 136/, and, at some e nergies, Rb/sup 83 and Cs/sup 135/. In addition, the independent yield of Ba/sup 131/ and the chain yields of Cs/sup 125/, Cs/sup 127/, Cs/sup 129/, La/sup 131/, Cs/sup 135/, Cs/sup 137/, ion cross sections of the Cs and Ba products on the neutron- excess side of stability decrease monotonically with increasing energy above 0.1 Bev, whereas the excitation functions for independent formation of the more neutron-deficient products in the Cs-Ba region and of Rb/sup 84/ and Rb/sup 86/ all go through maxima. The proton energies at which these maxima occur fall on a smooth curve when plotted against the neutronproton ratio of the product, with the peaks moving to higher energies with decreasing neutron-proton ratio. Under the assumption that the mass-yield curve in the region 125 < A < 140 is rather flat at each proton energy, the crosssection data in the Cs region can be used to deduce the charge dispersion in this mass range. Plots of log sigma vs N/Z (or Z--Z/sub A/) show symmetrical bell-shaped peaks up to a bombarding energy of 0.38 Bev, with full width at halfmaximum increasing from 3.3 Z units at 0.10 Bev to about 5 Z units at 0.38 Bev, and with the peak position (Z/sub p/) moving from Z/ sub A/ -- 1.44 to Z/sub A/ -- 0.85 over the same energy range. At all higher energies, a double-peaked charge distribution was found, with a neutron-excess peak centered at N/Z approximates 1,515(Z/sub p/ approximates Z/sub A/ -- 1.9), and having approximately constant width and height at bombarding energies greater than 1 Bev. The peak on the neutron-deficient side which first becomes noticeable at 0.68 Bev appears to become broader and shift slightiy to smaller N/ Z values with increasing energy, The two peaks are of comparable height in the Bev region, and the peak-to-valley ratio is only approximates 2. The total formation cross section per mass number in the Cs region decreases from approximates 52 mb at 0.1 Bev to about 29 mb at 1 Bev and then stays approximately constant; the contribution of the neutron-excess peak above 1 Bev is about 12 mb. The neutron-excess peak corresponds in width and position to that obtained in fission by approximates 50-Mev protons. The recoil behavior of Ba/sup 140/ lends support to the idea that the neutron-excess products are formed in a lowdeposition-energy process. The recoil behavior of Ba/sup 131/ indicates that it is formed in a high-deposition-energy process. Post-fission neutron evaporation is required for the observed characteristics of the excitation functions of the rubidium isotopes and the neutron-deficient species in the Cs region. The correlation between neutron-proton ratios and positions of excitation function maxima is semiquantitatively accounted for if fission with unchanged charge distribution, followed by nucleon evaporation, is assumed. (auth) 
</span>
4 0
3 years ago
Match with the correct definition.
andre [41]

Answer:

Ionic bonding: C

Covalent bonding: B

Metallic bonding: D

Pauli exclusion principle: A

Explanation:

All the electrons in 1 atom are characterized by a series of 4 numbers, known as quantum numbers. These numbers (n, l, ml, ms) describe the state of each electron (in which level, sublevel, orbital it is and its spin). For 2 electrons to coexist in the same atom they must differ in at least of these numbers. If they occupy the same level, sublevel and orbital, then they must have different (and opposite) spins. This is known as Pauli exclusion principle.

Also, to gain stability atoms can gain, lose or share electrons. In doing so they form bonds. There are 3 kinds of bonds:

  • Ionic bonding: these are formed between metals and nonmetals. Metals tend to lose electrons and form cations (positive ions) and nonmetals tend to gain electrons and form anions (negative ions). Cations and anions attract each other due to <em>electrostatic forces</em> between <em>oppositely charged ions</em>.
  • Covalent bonding: these are formed between nonmetals, which share pairs of electrons so as to reach the <em>electron configuration</em> of the closest noble gas (the most stable electron configuration).
  • Metallic bonding: valence electrons are loose in metals, so they move together as a "sea of electrons", acting as <em>"glue"</em> of the remaining positive <em>cores</em> (electrons that are negative charges serve to attract the positive charges of the cores).
8 0
3 years ago
How many types of nomenclature in the features of organic chemistry? What are they?
12345 [234]

Answer:

there are two types of nomenclature used in organic system. the most widely used and universally accepted system of nomenclature is the IUPAC system of nomenclature. some compounds are referred to by their common name that existed before the IUPAC system or is more widely known than the IUPAC names.

Explanation:

IUPAC ( international union of pure and applied chemistry) system of nomenclature is used to name compounds in organic system. there are some principles to be followed while using this nomenclature. some of them are:-

1) identification of parent chain is the first step. the longest hydrocarbon chain is the parent chain.

2) identification of all the substituent groups of the parent chain is also required.

3) hydrocarbon cyclic ring has a fixed prefix and  that is cyclo.

5 0
3 years ago
How much is 35° C in F?
Furkat [3]
It's 95 F
The formula is the following:
T
4 0
4 years ago
8. Balance the following nuclear equations:<br> ^65/30Ca -&gt; ^65/29Sc +_______
a_sh-v [17]

Explanation:

          ⁶⁵₃₀Ca   →   ⁶⁵₂₉Sc  +   ⁿₓH

The reaction above is nuclear reaction.

In a nuclear reaction, the mass number and atomic number must be conserved.

The mass number is the superscript before the atom

Atomic number is the subscript before the atom

  Conserving mass number:

       65 = 65 + n

        n = 0

   conserving atomic number:

    30 = 29 + x

     x = 1

The unknown atom is a positron i.e a positively charged electron:   ⁰₁e

              ⁶⁵₃₀Ca   →   ⁶⁵₂₉Sc  +  ⁰₁e

learn more:

Transmutation brainly.com/question/3433940

#learnwithBrainly

3 0
3 years ago
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