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Paladinen [302]
4 years ago
12

Why does a scientist form a hypothesis?

Chemistry
1 answer:
Kryger [21]4 years ago
8 0
Answer: B (to provide a statement that can be tested with an experiment
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How did Wegener work out what Pangea looked like?
spayn [35]

Answer:

ok so basicalkly he lloked at how the subdiction zone formed and where previus conintal drift occured

Explanation:

8 0
3 years ago
PLZ HELP!
Setler [38]

Answer:

The answer is RNA

Explanation:

Each sequence of three nucleotides, called a codon, usually codes for one particular amino acid. (Amino acids are the building blocks of proteins.) A type of RNA called transfer RNA (tRNA) assembles the protein, one amino acid at a time.

7 0
3 years ago
Read 2 more answers
HC1 solution is mostly water. NaOH solution is mostly water. When 50mL of HC1 is mixed with 50mL of NaOH, what is the final mass
elixir [45]
Since water has a density of about 1g/mL, and we are assuming HCl and NaOH are mostly water, the total mass of the 2 solutions is 100 g.
Due to the conservation of mass, the mass of product must equal the total mass of reactant, therefore the final mass must also be 100 g.
5 0
4 years ago
A 3.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
andrew-mc [135]

Answer: The molecular formula for the given organic compound X is C_6H_{8}O_7

Explanation:

We are given:

Mass of CO_2=4.13g

Mass of H_2O=1.13g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 4.13 g of carbon dioxide, =\frac{12}{44}\times 4.13=1.13g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.13 g of water, \frac{2}{18}\times 1.13=0.125g of hydrogen will be contained.

Mass of oxygen in the compound = (3.00) - (1.13+ 0.125) = 1.75 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.13g}{12g/mole}=0.094moles

Moles of Hydrogen =\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.125g}{1g/mole}=0.125moles

Moles of Oxygen =\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.75g}{16g/mole}=0.109moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles

For Carbon = \frac{0.094}{0.094}=1

For Hydrogen = \frac{0.125}{0.094}=1.33

For Oxygen = \frac{0.109}{0.094}=1.16

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1: 1.33: 1.16

Converting them into whole number ratios by multiplying by 6:

The ratio of C : H : O = 6: 8: 7

Hence, the empirical formula for the given compound is C_6H_8O_7

Empirical mass = 6\times 12+8\times 1+7\times 16=192g

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

Putting values in above equation, we get:

n=\frac{192g/mol}{192g/mol}=1

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_6H_8O_7\times 1=C_6H_{8}O_7

Thus molecular formula for the given organic compound X is C_6H_{8}O_7

7 0
3 years ago
How many g are equal to 345.7 mg? what conversion factor will you use
Over [174]

Answer:

0.3477 grams

The conversion factor is 1/1000

Explanation:

347.7 mg = 0.3477 grams

1 mg = 1x10⁻³ g

1 g / 1000 mg . 347.7 mg = 0.3477 grams

3 0
3 years ago
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