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3 years ago

Explain how a fish is able to enjoy 180° field of view when in a pond.

Physics

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

Time

An explanation of basic pond measurements that are vital to basic pond management practices.

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Pond Measurements: Area, Volume and Residence Time - Articles UPDATED: OCTOBER 29, 2015

Pond Measurements: Area, Volume and Residence Time

The importance of getting an accurate estimation of your pond surface area cannot be overestimated. The majority of pond owners visually estimate their pond area, which usually results in an overestimate of the true pond surface area. Pond area and water volume should be calculated based on some simple measurements. The effort necessary to estimate pond surface area is directly related to your pond's shape and uniformity. The simplest method--using basic equations for common shapes--can be applied if your pond closely resembles a circle, square, rectangle, or trapezoid in shape.

Pond Shapes

Circular

pond shape can be estimated by measuring the distance around the pond shoreline in feet. Square the shoreline distance and divide by 547,390 to get the pond area in acres. For example, a pond that is 450 feet around the shoreline would have an area = (450 feet)2 / 547,390 or 0.37 acres.

Explanation:

i looked this up

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The car has traveled 2.4 miles

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3 years ago

At one point in space, the electric potential energy of a 15 nC charge is 42 μJ . Part A) What is the electric potential at this

Anastasy [175]

Answer:

Part A:

$\rm 2.8\times 10^3\ Volts.$

Part B:

$\rm 5.6\times 10^{-5}\ J.$

Explanation:

Part A:

Potential energy of charge at the given point, $\rm U=42\ \mu J=42\times 10^{-6}\ J.$

Charge, $\rm q=15\ nC = 15\times 10^{-9}\ C.$

The potential energy at a point due to a charge is defined as

$\rm U=qV$ .

where,

V = electric potential at that point.

Therefore,

$\rm V=\dfrac{U}{q}=\dfrac{42\times 10^{-6}}{15\times 10^{-9}}=2.8\times 10^3\ Volts.$

Part B:

Now, if the charge at that point is replaced with $\rm q_1 = 20\ nC = 20\times 10^{-9}\ C.$ , then the electric potential energy at that point is given by

$\rm U=q_1V = 20\times 10^{-9}\times 2.8\times 10^3=5.6\times 10^{-5}\ J.$

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3 years ago

A boy rows a rowboat across a river. The boat moves at 4.3 m/s at a direction of 25°

NikAS [45]

East component: 3.9 m/s

South component: 1.8 m/s

Explanation:

We have to resolve the velocity vector along the east and south axis.

Taking east as positive x-direction and south as positive y-direction, the components of the velocity are given by:

$v_x = v cos \theta\\v_y = v sin \theta$

where

v = 4.3 m/s is the magnitude of the velocity

$\theta=25^{\circ}$ is the angle between the direction of the velocity and of the x-axis

Substituting into the equations, we find:

East component:

$v_x = (4.3)(cos 25^{\circ})=3.9 m/s$

South component:

$v_y = (4.3)(sin 25^{\circ})=1.8 m/s$

Learn more about vector components:

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4 years ago

When an object is getting closer to us , it emits redder light . True or False

Andrei [34K]

True I think.............

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4 years ago

Read 2 more answers

Wind instruments like trumpets and saxophones work on the same principle as the "tube closed on one end" that we examined in our

Gnom [1K]

Answer:

f = v / 4L

the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.

Explanation:

In wind instruments the wave speed must meet

v = λ f

λ = v / f

from v is the speed of sound that depends on the temperature

v = v₀ $\sqrt{1+ \frac{T [C]}{273} }$

where I saw the speed of sound at 0ºC v₀ = 331 m/s the temperature is in degrees centigrade, we can take the degrees Fahrenheit to centigrade with the relation

(F -32) 5/9 = C

76ºF = 24.4ºC

45ºF = 7.2ºC

With this relationship we can see that the speed of sound is significantly reduced when leaving the house to the outside

at T₁ = 24ºC v₁ = 342.9 m / s

at T₂ = 7ºC v₂ = 339.7 m / s

To satisfy this speed the wavelength of the sound must be reduced, so the resonant frequencies change

λ / 4 = L

λ= 4L

v / f = 4L

f = v / 4L

Therefore, the frequency of the instruments is reduced by the decrease in the speed of the wave with the temperature.

3 0

3 years ago

Explain how a fish is able to enjoy 180° field of view when in a pond.​

Explain how a fish is able to enjoy 180° field of view when in a pond.