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sdas [7]
3 years ago
12

1. what kinds of things do scientists in each area study?2. how do scientists answer questions?​

Physics
1 answer:
solong [7]3 years ago
6 0

Answer:

they think of new things to create

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A person is standing on a level floor. His head, upper
BabaBlast [244]

Answer:

y_{cg} = 1.03 m

Explanation:

Given data:

weigh (head+arms + head) w_1 = 438 N

centre of gravity y_1= 1.28 m

weigh (upper leg) w_2 = 144 N

Center of gravity y_2 = 0.760 m

weigh ( lower leg + feet) = 87 N

centre of gravity = y_3 = 0.250 m

location of center of gravity = \frac{w_1 y_1 + w_2 y_2 + w_3 y_3}{w_1 +W_2 +w_3}

y_{cg} = \frac{438 \times 1.28 + 144\times 0.760 + 87 \times 0.250}{438+144+87}

y_{cg} = 1.03 m

8 0
4 years ago
Two identical loudspeakers 2.30 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
Dimas [21]

Answer:

Abby is standing (4.5^2 + 2.3^2)^1/2   from the far speaker

D2 = 5.05 m from the far speaker

The difference in distances from the speakers is

5.05 - 4.5 = .55 m     (Let y be wavelength, lambda)

n y = 4.5

(n + 1) y = 5.05 for the speakers to be in phase at smallest wavelength

y = .55 m          subtracting equations

f = v / y = 340 / .55 = 618 / sec     should be the smallest frequency

8 0
3 years ago
A parachutist's fall to Earth is determined by two opposing forces. A gravitational force of 605 N acts on the parachutist. Afte
Doss [256]

Answer:15.8 m/s

Explanation:

Given

Gravitational Force F_g=605 N

Air resistance F_d=689 N

mass of Parachutist =\frac{605}{9.8}=61.73 kg

Velocity after 3 s

v=u+at

v=0+9.8\times 3

v=29.4 m/s

Now Parachutist opens the parachute

Net for on Parachutist

605-689=-84

84 N drag force

therefore deceleration \frac{84}{61.73}=1.36 m/s^2

velocity after 10 s is

v_1=v+at

v_1=29.4-1.36\times 10

v_1=15.8 m/s

7 0
4 years ago
Air is forced from the bottom of a rocket and it lifts off. This
TEA [102]

Answer:

balanced force should be correct answer

5 0
4 years ago
Read 2 more answers
Calculate the potential energy of a 6kg bowling ball suspended 3m above the surface of the earth
Valentin [98]

Answer:  176.4 Joules

Explanation: Potential energy of a body is defined as the energy possessed by virtue of position.

Potential energy =m\times g\times h

m = mass of the body = 6 kg

g = acceleration due to gravity = 9.8 ms^{-2}

h = height of body = 3 m

Potential energy =6 kg\times 9.8ms^{-2}\times 3m=176.4kgm^2s^{-2}

= 176.4Joules                 {1kgm^2s^{-2}=1Joule}


8 0
3 years ago
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