Answer:
Explanation:
For the reaction
C2H5OH (l) + 3 O2(g) = 2CO2(g) + 3 H2O
We can calculate the standard molar enthalpy of combustion using the standard enthalpies of formation of the species involved in the reaction according to Hess law:
ΔHºc = 2ΔHºf CO2 (g) + 3ΔHºfH2O(l) - ( ΔHºf C2H5OH (l) - 3ΔHºfO2 (g) )
( we were not give the water state but we know we are at standard conditions so it is in its liquid state )
The ΔHºfs can be found in appropiate reference or texts.
ΔHºc = 2ΔHºf CO2 (g)+ 3ΔHºfH2O(l) - ( ΔHºf C2H5OH (l) -+3ΔHºfO2 (g) )
= [ 2 ( -393.52 ) + 3 ( -285.83 ) ] - [( -276.2 + 0 ) ] kJ
ΔHºc = -1368.33 kJ
In living things, the source of the carbon-14 that is used in radiocarbon dating is carbon dioxide in the atmosphere.
Living things inhale oxygen, and exhale carbon dioxide into the atmosphere, which is why the air and atmosphere are so full of it.
Electron transitions from higher to lower energy levels cause emission of energy in the form of electromagnetic waves, each with their own specific wavelength. Because the energy levels of elements are quantized, each transition has a specific energy difference. The collection of these transitions makes up the emission spectrum and each spectrum is unique to a specific element, allowing identification.
Answer:
phosphodiester bond
Explanation:
<em>Phosphodiester linkage/bond is found in deoxyribonucleic and ribonucleic acids. It is formed from a reaction involving the elimination of water from a reaction involving the hydroxyl groups of two different 5-carbon (pentose) sugars and a phosphate group.</em>
The elimination of water, also known as condensation reaction occur twice, resulting in the formation of two ester bonds which then bind the phosphate group to the pentose sugars to become a phosphodiester bond.
The bond links the 3'-hydroxyl group of one of the pentose sugars and the 5'-hydroxyl group of the other pentose sugar in the nucleotides that make up nucleic acids.
Answer:
a) alkali metals
Explanation:
The element described above definitely belonged to the alkali metals, the first group on the periodic table. They show the properties indicated in the text.
- They are metals because only metals are lustrous and malleable. This eliminates the possibility of them being halogens and noble gases.
- Only group 1 metals reacts vigorously with water to form alkali.
- Alkali are aqueous solutions that are basic in nature.
- The reactivity of group 1 metals is due to their one extra electrons in the outer most shell.
- These electrons are easily and readily lost in order for such atoms to gain stability and replicate the nearest noble gases.
- The most reactive metal belongs to this group elements.
- This is why it is nearly impossible to find them occurring alone in free state.
- Some of the elements in this group are Li, Na, K, Rb, Cs and Fr.
- Transition metals have variable oxidation states and some can be found alone in nature.
