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3 years ago

What is the answer and why

Physics

1 answer:

katen-ka-za [31]3 years ago

4 0

Answer:

The distance between gas species are assumed to be large.

Explanation:

Hello!

In this case, since the ideal gas condition is a hypothetical state of gases at which they are at low pressure and high temperature, because it is assumed the molecules are neither attracted nor repelled by each other, we can infer that the correct statement is "the distance between gas species are assumed to be large" because the low pressure and high temperature ensure the molecules are far away from each other and therefore allowing the ideal equation to be used to model the case, otherwise a rigorous equation of state such as Peng-Robinson, Redlich-Kwong and other should be used to model it as gases actually undergo interaction between their molecules.

Best regards!

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A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o

Ksju [112]

Answer:

71.4583 Hz

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Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

$f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz$

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

$\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m$

The fundamental frequency of the wire is given by

$f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N$

The tension in the wire is 67.9064 N

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Explanation:

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Answer:

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