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Contact [7]
3 years ago
11

You recently purchased a home four blocks from the busy tollway. On a typical evening, the decibel level resulting from tollway

traffic is 62 dB at the location of your house. Determine the decibel level on the same evening at a house 1 block from the tollway (four times closer).
Physics
1 answer:
inn [45]3 years ago
5 0

Answer:

74dB

Explanation:

Sound intensity is inversely proportional to the square of the distance. Thus, a house four times closer hears a sound 16x more intense.

The dB scale is logarithmic, so 16x louder than 62 dB is equal to

62 + 10*log(16) ~= 62 + 12 = 74dB

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The prominent sea floor feature that is found in the central Atlantic Ocean is the Mid-Atlantic Ridge. 
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3 years ago
Driving on asphalt roads entails very little rolling resistance, so most of the energy of the engine goes to overcoming air resi
nirvana33 [79]

Answer:

a) F = 882.63\,N, b) \dot W= 4413.15\,W, c) \eta = 15.216\,\%.

Explanation:

a) Let assume that car travel on a horizontal surface. The equations of equilibrium of the car are:

\Sigma F_{x} = F - \mu_{r}\cdot N = 0

\Sigma F_{y} = N - m\cdot g = 0

After some algebraic handling, the following expression for the propulsion force is constructed:

F = \mu_{r}\cdot m \cdot g

F = (0.06)\cdot (1500\,kg)\cdot (9.807\,\frac{m}{s^{2}} )

F = 882.63\,N

b) The power require to move the car at a speed of 5 meters per second is:

\dot W = F\cdot v

\dot W = (882.63\,N)\cdot (5\,\frac{m}{s} )

\dot W= 4413.15\,W

c) The efficiency of the car is:

\eta = \frac{(882.63\,N)\cdot (15\,mi)\cdot (\frac{1609\,m}{1\,mi} )}{(1.4\times 10^{8}\,J)} \times 100\,\%

\eta = 15.216\,\%

3 0
3 years ago
How does emission spectra occur?
Lerok [7]

The frequencies of light that an atom can emit are dependent on states the electrons can be in. When excited, an electron moves to a higher energy level or orbital. When the electron falls back to its ground level the light is emitted.

hope this helped:)

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4 0
3 years ago
A car increased its velocity to 62m/s in 10s starting from rest. Calculate the distance it covers during this time?
Roman55 [17]

Answer:

distance= velocity ×time

distance= 62×10

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6 0
3 years ago
Read 2 more answers
an object weighting 100g is thrown upwards from the ground at a speed of 100 m/s.where will the potential energy of the object b
Kay [80]

Answer:

333.3 m

Explanation:

Given

m =100g\ =\  0.1kg\\v = 100 m/s\\g = 10 m/s ^2

Potential energy =\frac{2}{3}\  of\  Kinetic\  energy......Equation(1)

We know that

Potential energy=mgh

Kinetic energy =\frac{1}{2} mv^{2}

Now From the Equation(1)

mgh=\frac{2}{3}*\frac{1}{2} mv^{2}\\  gh=\frac{v^{2} }{3} \\10 * h=\ \frac{10000}{3}\\ h=\ \frac{1000}{3} \\h=333.3\  m

3 0
2 years ago
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