Concentration of solution is 20%
Mass of solute( common salt) is 80g
take the amount of water as x
mass of the solvent = (80+x)
We know, concentration of solution = (mass of solute/mass of solution)×100
20=(80/80+x)×100
80+x=80×5 ( we devide the both side by 20)
x= 400-80
x=320 g
The correct option is A.
The law of definite proportion states that a given chemical compound always contains its component elements in fixed ratio irrespective of the source they are obtain from.
For instance, water is made up of two atoms of hydrogen and one atom of oxygen. Water can not be formed in any other way. Combining the oxygen and the hydrogen in another ratio will give us another thing not water.
Quantitative data because it involves a number (quantity)
Answer:
7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100 M solution.
Explanation:
First of all the molecular weight of Na2SO4 is 142.08 gram.Now we all know that if the molecular weight of a compound is dissolved in 1000ml or 1 litee of water then the strength of that solution becomes 1 M.
According to the given question we have to prepare 0.100 M solution
1000 ml of solution contain 142.08×0.1= 14.208 gram Na2SO4
1 ml of solution contain 14.208÷1000= 0.014 gram
0.5L or 500ml of solution contain 0.014×500= 7gram Na2SO4.
So it can be stated that 7 gram of Na2SO4 should be required to prepare 0.5L of a 0.100M solution.
