Answer:
B. the triangle in question is not a right triangle
Step-by-step explanation:
A 3-4-5 triangle is a right triangle, so this one, with its longer longest side, is an obtuse triangle. It is not a right triangle.
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3, 4, 5 is one of the first Pythagorean triples that you learn:
3² + 4² = 5²
These are the side lengths of the smallest right triangle with integer sides. It is worthwhile to remember. This triple is used not only in many math problems (such as this one), but also in real life when it is useful to lay out a right angle.
Alladin because it’s a name
Answer:
The quotient = 4x - 17 and the remainder = 54
Step-by-step explanation:
The quotient = 4x - 17 and the remainder = 54
"Will is twice as old as Jill."
Jill's age . . . . . J
Will's age . . . . 2J .
"Three years ago . . .
Jill's age then . . . . . J - 3
Will's age then . . . . 2J - 3
". . . Jill's age then was 2/5 of Will's age then."
J - 3 = (2/5) (2J - 3)
Multiply
each side by 5 : 5J - 15 = 2 (2J - 3)
Divide
each side by 2 : 2.5 J - 7.5 = 2J - 3
Subtract 2J
from each side: 0.5 J - 7.5 = -3
Add 7.5
to each side: 0.5 J = 4.5
Multiply
each side by 2 : J = 9
Jill is 9 y.o. now.
Will is 18 y.o. now.
We have been given that Judy’s brother Sam has a collection of 96 comic books. We have been asked to find the 10 ways Sam could divide his comic books into equal groups.
This can be done as follows:
96 can be written as 
. Thus, we can either have 2 groups of 48 comics or 48 groups of 2 comics. As we can see we have 2 ways to divide the comic books in equal groups.
Likewise, 96 can also be written as 
. Here, we can similarly see that we can either have 3 groups of 32 comics or 32 groups of 3 comics. As we can again see we have 2 more ways to divide the comic books in equal groups, taking the total number of ways to 4.
Continuing in this manner we will see that we can have 4 groups of 24 or 24 groups of 4, 6 groups of 16 or 16 groups of 6 and lastly 12 groups of 8 or 8 groups of 12 comic books, thus taking the count to a <u>total of 10 ways</u> in which Sam can divide his comic books into equal groups.
Our question has been answered.
