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insens350 [35]
3 years ago
14

CORRECT ANSWER GETS BRAINEST!!! Which element is in Group 6, Period 4? (Look at image)

Chemistry
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer:

Se

Explanation:

Se is in geoup 6, period 4

Alekssandra [29.7K]3 years ago
3 0
Se

Se is on the group 6, period 4
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g When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solut
Elden [556K]

Answer:

When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solution of sodium chloride. Write the conventional equation, total ionic equation, and net ionic equation for this reaction.

Explanation:

The word equation for the reaction is:

Copper (II) chloride(aq) + sodium carbonate (aq) ->sodium chloride (aq) +           copper carbonate(s)

The balanced chemical equation of the reaction is:

CuCl_2(aq)+Na_2CO_3(aq)->2NaCl(aq)+CuCO_3(s)

The complete ionic equation is:

Cu^2+(aq)+2Cl^-(aq)+2Na^+(aq)+CO_3^2^-(aq)->2Cl^-(aq)+2Na^+(aq)+CuCO_3(s)\\

The net ionic equation is obtained from the complete ionic equation after removing the spectator ions:

Cu^2^+(aq)+CO_3^2^-(aq)->CuCO_3(s)

5 0
3 years ago
In water, bases form _____.
atroni [7]
A base produces hydroxide ion in water
5 0
4 years ago
Read 2 more answers
Convert 6.62 X 10^23 atoms to moles
olga2289 [7]

Answer:

1.099

Explanation:

Hope this helps

5 0
3 years ago
Read 2 more answers
32
myrzilka [38]

Answer:

0.305 mol

Explanation:

Ca(NO) is not a molecule. I think you meant to type Ca(NO3)2, which is calcium nitrate.

The moles of a compound is equal to is mass divided by its molar mass.

The molar mass of Ca(NO3)2 is 164.09 g/mol.

50.0 / 164.09 = 0.305

6 0
2 years ago
How many moles of Kr are contained in 398 mg of Kr?
bagirrra123 [75]
The mass of 1 mole of an element is its atomic weight on the Periodic Table in grams.

1g = 1000mg

The mass of 1 mole of Kr = 83.80g Kr

Convert mg Kr to g Kr.

398mg Kr x (1g/1000mg) = 0.398g Kr

Convert g Kr to mol Kr.

0.398g Kr x (1mol Kr/83.80g Kr) = 4.75x10-3mol Kr
8 0
3 years ago
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