Answer:
because the water in a bottle has been purified
Explanation:
These are known to be saturated.
The definition of a saturated fatty acid is that the carbon chain coming off of the acid group contains only single bonds. An unsaturated fatty acid contains at least one double bond in the carbon chain coming off of the acid group. Saturated fats are usually fats (solid at room temperature) while unsaturated fats can be oils (liquid at room temperature) this is because the single bonds in the saturated fats give the molecule a shape that can stack on another saturated fat molecule more easily which makes the melting points higher. The double bonds (usually referring to cis double bonds since trans double bonds are in trans fats) in unsaturated fats give the molecule a shape that cannot stack on another unsaturated fat molecule easily which makes the melting point lower.
I hope this helps. Please let me know if anything is unclear or if you want further explanation.
<span>You have to use an activity series and then predict which metal by itself will replace the metal inside of the compound. These all appear to be single replacement reactions.</span>
Answer:
26.74g
Explanation:
The equation of the reaction is;
SIO₂ + 3C --> SiC +2CO
From the balanced equation, the relationship between SiC and C is;
3 mol of C produces 1 mol of SiC
Converting mol to mass using; Mass = moles * Molar mass
Mass of SiC = 1 mol * 40.11 g/mol = 40.11g
This means;
3 mol of C produces 40.11g of SiC
2 mol of C produces xg of SiC
3 = 40.11
2 = x
x = 2 * 40.11 / 3 = 26.74g
The given question is incomplete. The complete question is
If 1.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C∘C, what is the equilibrium concentration of H2 (g). Given the equilibrium constant is 62.
Answer: The equilibrium concentration of
is 0.498 M
Explanation:
Initial concentration of
= 1.0 M
The given balanced equilibrium reaction is,

initial (1.0) M 0 0
At eqm (1.0-2x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[H_2]\times [I_2]}{[HI]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5Ctimes%20%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
Now put all the given values in this expression, we get :

By solving we get :

Thus the equilibrium concentration of
is 0.498 M