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adoni [48]
3 years ago
14

Un avión da "una vuelta mortal" de radio R = 500 m con una celeridad constante v = 360 km/h. Halla la fuerza ejercida por el asi

ento sobre el piloto, si su masa es m = 70 kg, en las partes inferior y superior de la trayectoria circular.
Physics
1 answer:
Airida [17]3 years ago
8 0

Answer:

1400 N

Explanation:

Verá, durante el salto mortal, el piloto se mueve en una trayectoria circular y la fuerza que actúa sobre él es una fuerza centrípeta.

Sea la fuerza centrípeta F, la masa del piloto (m) = 70 Kg, el radio (r) = 500 my la velocidad (v) = 360 km / hr * 1000/3600 = 100 m / s

F = mv ^ 2 / r

F = 70 * (100) ^ 2/500

F = 1400 N

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A mass m at the end of a spring vibrates with a frequency
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Answer:

m = 0.59 kg.

Explanation:

First, we need to find the relation between the frequency and mass on a spring.

The Hooke's law states that

F = -kx

And Newton's Second Law also states that

F = ma = m\frac{d^2x}{dt^2}

Combining two equations yields

a = -\frac{k}{m}x

The term that determines the proportionality between acceleration and position is defined as angular frequency, ω.

\omega = \sqrt{\frac{k}{m}}

And given that ω = 2πf

the relation between frequency and mass becomes

f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}.

Let's apply this to the variables in the question.

0.88 = \frac{1}{2\pi}\sqrt{\frac{k}{m}}\\0.60 = \frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}\\\frac{0.88}{0.60} = \frac{\frac{1}{2\pi}\sqrt{\frac{k}{m}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m+0.68}}}\\1.4667 = \frac{\sqrt{m+0.68}}{\sqrt{m}}\\2.15m = m + 0.68\\1.15m = 0.68\\m = 0.59~kg

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3 years ago
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D. freezing, deposition, and condensation

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In order to understand, let's see the definition of these changes of state:

- freezing: freezing occurs when a substance changes from liquid state to solid state

- deposition: deposition occurs when a substance changes from gas state to solid state, without passing through the liquid state

- condensation: this process occurs when a substance changes from gas state to liquid state

In all the three processes listed above, energy is released from the substance, which in fact loses energy. In fact:

- in a liquid, the particles have more energy than in a solid (because in liquid they can move, while in solid they can only vibrate), so during freezing, since a liquid turns into a solid, it releases energy to the surrounding

- in a gas, the particles have more energy than in a liquid (because in a gas they can move faster than in a liquid), so during condensation, since a gas turns into a liquid, energy is released to the surrounding

- in deposition, the particles change from the gas state (where they move faster) to a solid state (where they are not free to move), so they lose energy as well.

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