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3 years ago

13

Does anyone else have this packet for Principles of Engineering? I'm lost on everything and just need the equations to start the

problem and then I'm good lol PLEASE HELP

1 answer:

rjkz [21]3 years ago

3 0

Ask your math friends or whatever bevause this is hard

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758 j of heat are added to 0.750 kg of copper. how much does its temperature change?(unit=degrees c) PLEASE HELPPPPPPP MEEEEEE

DiKsa [7]

Answer:

$2.6^{\circ}C$

Explanation:

When a substance is supplied with a certain amount of heat energy, the temperature of the substance increases according to the equation

$Q=mC\Delta T$

where

m is the mass of the substance

Q is the amount of energy supplied

C is the specific heat of the substance

$\Delta T$ is the temperature change

In this problem:

Q = 758 J is the energy supplied

m = 0.750 kg is the mass of the sample

$C=385 J/kg^{\circ}C$ is the specific heat of copper

Re-arranging the equation, we can find the increase in temperature:

$\Delta T=\frac{Q}{mC}=\frac{758}{(0.750)(385)}=2.6^{\circ}C$

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3 years ago

Most people in south and south east Asia live in

Dimas [21]

Answer small rual villages

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3 years ago

A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area of 0.700 m2 .

Annette [7]

Answer

given,

Area = 0.7 m²

electric field of wave = 0.0400 V/m

time = t =30 s

intensity of electromagnetic wave

$I = \dfrac{E_0^2}{2\mu_0c}$

$E_0^2 = 2 E_{rms}^2$

c is speed of light

$I = \dfrac{2E_{rms}^2}{2\mu_0c}$

$I = \dfrac{E_{rms}^2}{\mu_0c}$

$I = \dfrac{0.04^2}{4\pi \times 10^{-7}\times 3 \times 10^8}$

I = 4.24 x 10⁻⁶ W/m²

the amount of energy required

E = I A t

E = 4.24 x 10⁻⁶ x 0.7 x 30

E = 8.9 x 10⁻⁵ J

6 0

3 years ago

What is a electromagnet?

Art [367]

An electromagnet is a soft metal core which is made into a magnet by passing the electric current through a coil which is surrounding it.

7 0

3 years ago

Read 2 more answers

Musicians can use beats to tune their instruments. One flute is properly tuned and plays the musical note A at exactly 440 Hz. A

kodGreya [7K]

Answer:

439 Hz

Explanation:

$f_1$ = Frequency of first wave = 440 Hz

F = Beat frequency = 1 Hz

$f_2$ = Frequency of the instrument

The beat frequency is the difference of the two waves which are interacting with each other

$F=f_1-f_2\\\Rightarrow 1=440-f_2\\\Rightarrow f_2=440-1\\\Rightarrow f_2=439\ Hz$

The frequency of the instrument is 439 Hz

5 0

3 years ago