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luda_lava [24]
3 years ago
13

Does anyone else have this packet for Principles of Engineering? I'm lost on everything and just need the equations to start the

problem and then I'm good lol PLEASE HELP

Physics
1 answer:
rjkz [21]3 years ago
3 0
Ask your math friends or whatever bevause this is hard 
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A first order reaction, A -> products, has a rate reaction of .00250 Ms-1 when [A] = . 484 M. (a) What is the rate constant,
tamaranim1 [39]

Answer: a)  The rate constant, k, for this reaction is 0.00516s^{-1}

b) No t_{\frac{1}{2}} does not depend on concentration.

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

A\rightarrow products

Given: Order with respect to A = 1

Thus rate law is:

a) Rate=k[A]^1

k= rate constant

0.00250=k[0.484]^1

k=0.00516s^{-1}

The rate constant, k, for this reaction is 0.00516s^{-1}

b) Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant  

a - x = amount left after decay process  

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{2.303}{k}\log\frac{100}{50}

t_{\frac{1}{2}}=\frac{0.69}{k}

Thus t_{\frac{1}{2}} does not depend on concentration.

8 0
3 years ago
Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the
Lilit [14]

Answer:

Explanation:

The force of friction acting on the system

= .04 x 9.8 ( 10.2 + 7 )

= 6.74 N

Net force = 8.9 - 6.74

= 2.16 N

Acceleration in the system

= 2.16 /  ( 10.2 + 7 )

= .12558 m / s ²

Contact force between boxes = FP

Considering force on box A

Net force = 8.9 - FP

Applying Newton's law on box A

8.9 - FP = 10.2 x .12558

= 1.28

FP = 8.9 - 1.28

= 7.62 N

5 0
3 years ago
if your goal is to find a mentor who can help encourage you which category would that go fall into physical emotional social aca
Alborosie
Emotional because by encouraging you you're asking for emotional support
3 0
3 years ago
Suppose an oxygen molecule traveling at this speed bounces back and forth between opposite sides of a cubical vessel 0.17 m on a
Nastasia [14]

Answer: The last part of the question has some details missing which is ; (Assume that the molecule's velocity is perpendicular to the two sides that it strikes.) molecule v=482 m/s molecule momentum=2.56 x 10^(-23)

Explanation:

  • The momentum of the molecule is 2.56 x 10^(-23) .
  • Particle hits the wall and bounces.
  • Momentum is reversed. Change in momentum = impulse
  • This is Force x time.
  • Momentum change happens at a wall after each trip.

  • time required = distance /speed

  • = 0.17 X 2/(482 m/s)

  • Average force = impulse / time

  • = 2 x 482 x 2.56 x 10^(-23) / (0.17 x 2)

  • = 7.76 x 10^20N, is the average force the molecule exerts on one of the walls of the container.
3 0
4 years ago
What happens when a spinning ice skater draws in her outstretched arms? Group of answer choices Her moment of inertia increases
kotegsom [21]

Answer:

Her moment of inertia decreases causing her spin to speed up. The physics law behind this phenomenon is the conservation of angular momentum.

Explanation:

<em>Theory</em>

<u>The Law of conservation of angular momentum</u>

The angular momentum of a rotating body or a system remains constant unless it is acted upon by an external unbalance force.

Angular momentum = moment of inertia × angular velocity

The moment of inertia = mass×[perpendicular distance from axis of rotation]²

___________________________________________________________

⇒When skater draws in her outstretched arms the mass distribution get      concentrated towards the axis of rotation so the moment of inertia of the body decrease.

But angular moment should conserve so angular velocity  increases (spin increases)

5 0
3 years ago
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