Answer:
No
Explanation:
The force of tension exerted by the string on the rock acts as centripetal force, so its direction is always towards the centre of the circle.
However, the direction of motion of the rock is always tangential to the circle: this means that the force is always perpendicular to the direction of motion of the rock.
As we know, the work done by a force on an object is
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the force and the displacement
In this situation, F and d are perpendicular, so 
, therefore 
and the work done is zero:
I would think that you would multiply then divide
Answer: a) 42Nm b) 8.4m/s
Explanation:
Impulse is defined as object change in momentum.
Since Force = mass × acceleration
F = ma
Acceleration is the rate of change in velocity.
F = m(v-u)/t
Cross multiply
Ft = m(v-u)
Since impulse = Ft
and Ft = m(v-u)... (1)
The object change in velocity (v-u) = Ft/m from eqn 1
Going to the question;
a) Impulse = Force (F) × time(t)
Given force = 14N and time = 3seconds
Impulse = 14×3
Impulse = 42Nm
b) The object change in velocity (v-u) = Ft/m where mass = 5kg
v-u = 14×3/5
Change in velocity = 42/5 = 8.4m/s
Answer:
Explanation:
Given that,
Small wheel applied force
F₁ = 50N
Small wheel radius
r₁ = 18cm
Bigger wheel radius.
r₂ = 29cm
Bigger wheel applied force
F₂ =?
Since the combination of those forces did not cause the wheel to rotate,
Then, Στ = 0
F₁•r₁ —F₂•r₂ =
50×18 — 29F₂ = 0
900 = 29F₂
F₂ = 900 / 29
F₂ = 31.03 N
The pulling force applied at the larger wheel is 31.03N
