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Allushta [10]
3 years ago
10

33. A zebra is at rest 60 m away from a charging lion

Physics
1 answer:
Ann [662]3 years ago
3 0

Answer:

the lion will miss the zebra by 3 meters

Explanation

The zebra has gone 23.75m after 5 seconds

and the lion can only go 20 m/s

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An instrument that measures air pressure using a partially evacuated chamber is called a(n ________ barometer.
Jet001 [13]
The appropriate response is the Aneroid barometer. This kind of gauge has an incompletely cleared chamber that progressions shape, packing as barometrical weight increments and growing as weight declines.

I hope the answer will help you. 
6 0
3 years ago
How are step up transformers used in the transmission of electrical energy
tensa zangetsu [6.8K]

Answer:

Transformers are used to increase or decrease the voltage of AC currents

Explanation:

A transformer is a device consisting of two coils (called primary and secondary coil) wrapped at the two sides of a soft iron core. When an AC current is present in the primary coil, it induces a magnetic field inside the core, and the presence of this changing magnetic field induces a voltage (and a current) into the secondary coil.

The voltages in the primary and the secondary coil are related by the transformer equation:

\frac{V_p}{V_s}=\frac{N_p}{N_s}

where

Vp, Vs are the voltages in the primary and secondary coil

Np, Ns are the number of turns in the primary and secondary coil

There are two types of transformers:

- Step-up transformers: these have N_s > N_p, so that V_s > V_p, which means that they increase the voltage. They are used to increase the voltage of the AC current produced by the power plants, before being sent into the transmission lines.

- Step-down transformers: these have N_s < N_p, so that V_s < V_p, which means that they decrease the voltage. They are used at the end of the transmission lines, before the houses, in order to decrease the voltage and allow the household appliances to work properly (in fact, household appliances need lower voltages to work)

8 0
3 years ago
In a scale model of the Solar System, if the Sun is represented by a ball with a diameter of about 8 inches, about how large wou
Evgesh-ka [11]

Answer:

size of popcorn seed may meet the scaled earth size of x = 0.07312 in.  

Explanation:

Given:-

- The diameter of actual sun, Ds = 1.3927 * 10^6 km

- The diameter of model sun ball, ds = 8 in

- The diameter of the actual earth, De = 12,742 km

Find:-

How large would be the earth model

Solution:-

- We can use the actual diameters of the earth and sun to develop the ratio of earth diameter to that of sun. The direct ratio can be used to model the diameter of earth for the scale model

                                          Sun                   Earth

                     Actual :     1392700 km     12,742 km

                      Scale :           8 in                    x

- Use direct relations and solve for x:

                               x = (8 in)*(12,742 km ) / ( 1392700 km )

                              x = 0.07312 in.

- From the given options apple, grapefruit and marble diameters are larger than 1 inch. So only the size of popcorn seed may meet the scaled earth size of x = 0.07312 in.  

4 0
3 years ago
Read 2 more answers
Why are atoms arranged in periods ...???
Sati [7]
<span>A horizontal row in the periodic table, which signifies the total number of electron shells in an element's atom. A vertical column in the periodic table, which signifies the number of valence shell electrons in an element's atom.</span>
3 0
3 years ago
Read 2 more answers
If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol
Alex

This question is incomplete.Here is complete one

Consider a telescope with a small circular aperture of diameter 2.0 centimeters. If two point sources of light are being imaged by this telescope, what is the maximum wavelength (lambda) at which the two can be resolved if their angular separation is 3.0x10^-5 radians? Express your answer in nanometers

Answer:

λ =492nm

Explanation:

Given Data

diameter=2.0 cm

angular separation=3.0x10^-5 radians

λ=?

Solution

sin(theta) = 1.22 x λ /D

λ=(0.02×sin(3.0×10⁻⁵))/1.22

λ=492nm

6 0
4 years ago
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