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Snowcat [4.5K]
3 years ago
10

What latitudes experience both summer and winter?

Physics
1 answer:
sergiy2304 [10]3 years ago
7 0

There are only two times of the year when the Earth's axis is tilted neither toward nor away from the sun, resulting in a equal amount of daylight and darkness at all latitudes. These events are referred to as Equinoxes.The word equinox is derived from two Latin words - aequus (equal) and nox (night). At the equator, the sun is directly overhead at noon on these two equinoxes. How do the climatological temperature patterns follow the four seasons? The temperatures are pretty much the same when comparing early winter to late winter and pretty much the same when comparing early summer to late summer. However, late Fall is much colder than early Fall and late Spring is much warmer than early Spring. Why is that? The reason is linked to the changing of the solar sun angle during each season. In the Fall, the sun angle is always getting lower and in the Spring it is always getting higher. From this it would make sense that late Fall is much colder than early Fall and late Spring is much warmer than early Spring.  In the winter, the sun angle is INCREASING and in the summer the sun angle is DECREASING. This fact causes temperatures to be pretty much the same when comparing early winter to late winter and pretty much the same when comparing early summer to late summer. The cumulative cooling of the ground and ocean is partially offset by an increasing sun angle in the winter and the cumulative warming of the ground and ocean is partially offset by a decreasing sun angle in the summer. This causes the Spring and Fall seasons to seem much quicker in duration than the Summer and Winter seasons.

<h2><u>I know this is long... but does this help??</u></h2>
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A thin spherical shell has a radius of 0.70 m. An applied torque of 860 N m gives the shell an angular acceleration of 4.70 rad/
Artyom0805 [142]

Answer:

I=182.97\ kg-m^2

Explanation:

Given that,

Radius of a spherical shell, r = 0.7 m

Torque acting on the shell, \tau=860\ N

Angular acceleration of the shell, \alpha =4.7\ m/s^2

We need to find the rotational inertia of the shell about the axis of rotation. The relation between the torque and the angular acceleration is given by :

\tau=I\alpha

I is the rotational inertia of the shell

I=\dfrac{\tau}{\alpha }\\\\I=\dfrac{860}{4.7}\\\\I=182.97\ kg-m^2

So, the rotational inertia of the shell is 182.97\ kg-m^2.

7 0
3 years ago
The intensity of sunlight falling on the earth is about 1.4 kw/m2 (before any gets absorbed by our atmosphere). at what rate doe
xxTIMURxx [149]
The area of the Earth (Ae) that is irradiated by is given by:

Ae = 4πRe^2, where Re = Distance from Sun to Earth
Substituting;
Ae = 4π*(1.5*10^8*1000)^2 = 2.827*10^23 m^2

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6 0
3 years ago
Determine whether or not each of the following statement is true. If a statement is true, prove it. If the statement is false, p
Studentka2010 [4]

Answer:

True

Explanation:

This is a representation of Gauss law.

Gauss’s law does hold for moving charges, and in this respect Gauss’s law is more general than Coulomb’s law. In words, Gauss’s law states that: The net outward normal electric flux through any closed surface is proportional to the total electric charge enclosed within that closed surface. The law can be expressed mathematically using vector calculus in integral form and differential form, both are equivalent since they are related by the divergence theorem, also called Gauss’s theorem.

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3 years ago
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Bumek [7]

M = mass of the first sphere = 10 kg

m = mass of the second sphere = 8 kg

V = initial velocity of the first sphere before collision = 10 m/s

v = initial velocity of the second sphere before collision = 0 m/s

V' = final velocity of the first sphere after collision = ?

v' = final velocity of the second sphere after collision = 4 m/s

using conservation of momentum

M V + m v = M V' + m v'

(10) (10) + (8) (0) = (10) V' + (8) (4)

100 = (10) V' + 32

(10) V' = 68

V' = 6.8 m/s

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Answer:

A. a material burns out when current is excessive

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