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Snowcat [4.5K]
3 years ago
10

What latitudes experience both summer and winter?

Physics
1 answer:
sergiy2304 [10]3 years ago
7 0

There are only two times of the year when the Earth's axis is tilted neither toward nor away from the sun, resulting in a equal amount of daylight and darkness at all latitudes. These events are referred to as Equinoxes.The word equinox is derived from two Latin words - aequus (equal) and nox (night). At the equator, the sun is directly overhead at noon on these two equinoxes. How do the climatological temperature patterns follow the four seasons? The temperatures are pretty much the same when comparing early winter to late winter and pretty much the same when comparing early summer to late summer. However, late Fall is much colder than early Fall and late Spring is much warmer than early Spring. Why is that? The reason is linked to the changing of the solar sun angle during each season. In the Fall, the sun angle is always getting lower and in the Spring it is always getting higher. From this it would make sense that late Fall is much colder than early Fall and late Spring is much warmer than early Spring.  In the winter, the sun angle is INCREASING and in the summer the sun angle is DECREASING. This fact causes temperatures to be pretty much the same when comparing early winter to late winter and pretty much the same when comparing early summer to late summer. The cumulative cooling of the ground and ocean is partially offset by an increasing sun angle in the winter and the cumulative warming of the ground and ocean is partially offset by a decreasing sun angle in the summer. This causes the Spring and Fall seasons to seem much quicker in duration than the Summer and Winter seasons.

<h2><u>I know this is long... but does this help??</u></h2>
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3 years ago
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If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.70
Schach [20]

Answer:

The  radius is  R =  0.22 5 \  m

Explanation:

From the question we are told that

    The current is  I  =  61 \ A

     The  magnetic field is  B  =  1.70 *10^{-4} \  T

Generally the magnetic field produced by a current carrying conductor  is mathematically represented as

        B  =  \frac{\mu_o  *  I}{2 *  R }

=>     R  =  \frac{\mu_o  *  I  }{ 2 *  B }

Here  \mu_o is the permeability of free space with value  \mu_o  =  4\pi * 10^{-7} N/A^2

=>    R  =  \frac{  4\pi * 10^{-7}  *   61  }{ 2 *   1.70 *10^{-4} }

=>  R =  0.22 5 \  m

8 0
3 years ago
a 1150 kg car is on a 8.70 hill. using x-y axis tilted down the plane, what is the x-component of the normal force(unit=N)
rodikova [14]

The x-component of the normal force is equal to <u>1706.45 N.</u>

Why?

To solve the problem, and since there is no additional information, we can safely assume that the x-axis is parallalel to the hill surface and the y-axis is perpendicular to the x-axis. Knowing that, we can calculate the components of the normal force (or weight for this case), using the following formulas:

N_{x}=W*Sin(\alpha)=mg*Sin(\alpha)\\\\N_{y}=W*Cos(\alpha)=mg*Cos(\alpha)

Now, using the given information, we have:

mass=m=1150Kg\\\alpha=8.70\°\\g=9.81\frac{m}{s^{2}}

Calculating, we have:

N_{x}=mg*Sin(\alpha)

N_{x}=1150Kg*9.81\frac{m}{s^{2}}*Sin(8.70\°)\\\\N_{x}=11281.5\frac{Kg.m}{s^{2} }*Sin(8.70\°)=1706.45\frac{Kg.m}{s^{2} }=1706.45.23N

Hence, we have that the x-component of the normal force is equal to  <u>1706.45 N.</u>

Have a nice day!

3 0
4 years ago
What term is a force that can slow momentum <br><br> A. mass<br><br> B. friction
jenyasd209 [6]
Your answer is friction. Friction between to object slows the object down.
3 0
3 years ago
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You and your friends are driving down the road. Your car breaks down. You have to use a 1,210 N force to push the car 201 m to t
Katyanochek1 [597]

Answer:

2.43\cdot 10^5 J

Explanation:

Since the force applied is parallel to the displacement of the car, the work done on the car is simply given by:

W=Fd

where

F = 1210 N is the force applied on the car

d = 201 m is the displacement of the car

Substituting numbers into the equation, we find:

W=(1210 N)(201 m)=2.43\cdot 10^5 J

5 0
4 years ago
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