velocity of the projectile is given as

now the angle is given as 75 degree
so here we will have


now the time taken to reach the peak is given as


now the height moved by the projectile in same time is given as

now we have


so distance between the peak and projectile is given as

Answer:
(a) 
(b) 142
(c) 
(d) 96.8 mph
(e) 0.426 s
(f) 0.061 rad
Explanation:
Velocity is a time-derivative of position.
(a) 

(b) Since
is independent of
, it follows it was constant throughout. Hence, at any point or time, the horizontal velocity is 142.
(c) 

(d) When it passes the home plate, the ball has travelled 60.5 ft (from the question). This is horizontal, so it is equivalent to
.

.
In this time, the vertical velocity,
is

The speed of the ball at thus point is
ft/s
To convert this to mph, we multiply the factor 3600/5280

(e) The time has been determined from (d) above.

(f) This angle is given by

(Note here we are considering the acute angle so we ignore the negative sign)
In radians, this is
