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grin007 [14]
1 year ago
13

A 200 N object is resting on a surface with a coefficient of static friction equal to 0.15. A person pushes horizontally with a

force of 20 N. Calculate the magnitude of the force of friction.
Physics
1 answer:
Reika [66]1 year ago
3 0

Answer:

20 N

Explanation:

the force of static friction maximum = Fn * .15 = 200 * .15 = 30 N

  the force of friction will cancel out the 20 N force applied

    Ff = 20 N

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Tenemos.

Masa de la mesa = 20kg
Masa encima = 10kg
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Area de cada pata = 20cm² = 20cm² * 1/10000cm² * 1m² =0,002m²

Presió(P)n que se ejerce sobre cada pata.

P =F/A
P = Masa por gravedad/A Masa = 30kg Gravedad =9,8m/s²
P =(30kg * 9,8m/s²)/0,002m²
P = 294kg * m/s²/0,002m² Pero kg *m/s² = Nw
P = 294Nw0,002m²
P = 147000 Nw/m² Pero Nw/m² = pa
p =1,47 * 10⁵ pa

Respuesta.
La presión que se ejerce sobre cada pata es de 1,47 * 10⁵pa
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