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Xelga [282]
3 years ago
8

PLEASE HELP!!!! it would mean alot ! ​

Chemistry
2 answers:
statuscvo [17]3 years ago
6 0

Answer:

i looked it up its slinky waves

Explanation:

Dafna1 [17]3 years ago
3 0

Answer:

diffracted

Explanation:

Sure it might look like a slinky but if you're talking about waves then it's deffinetly diffracted hope this helps

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Why is steam distillation prefered over fractional distillation for the extraction of essencial oils?​
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Answer:

Because , the advantage of steam distillation over simple distillation is that the lower boiling point reduces decomposition of temperature-sensitive compounds. Steam distillation is useful for the purification of organic compounds, although vacuum distillation is more common

Explanation:

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What type of wave requires a medium to transfer energy?
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YYe the answer is mechanical
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Which of the following sentences describes oxygen at room temperature? (check all that apply)
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At room temperature, O2 is in gaseous state.

a gas has no definite volume or definite shape. It occupies volume of container and attains shape of container only.

Thus

It has no definite volume and takes the shape of its container.

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It has more energy than it would at a cooler temperature: the kinetic energy of gas molecules increases with increase in temperature. Thus the energy increases with temperature and decreases with decrease in temperature.


5 0
2 years ago
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This system has an equilibrium constant of 0.105 at 472°C: N2(g) + 3H2(g) ↔ 2NH3(g)
Kamila [148]

Answer:

What is the reaction quotient, Q, for this system when [N2] = 2.00 M, [H2] = 2.00 M, and [NH3] = 1.00 M at 472°C?

A. 0.0625

How does Q compare to Keq?

B. Q < Keq

Explanation:

5 0
3 years ago
A cubic piece of platinum metal (specific heat capacity = 0.1256 J/°C・g) at 200.0°C is dropped into 1.00 L of deuterium oxide ('
polet [3.4K]

Answer:

a=5.65cm

Explanation:

Hello,

In this case, for this heat transfer process in which the heat lost by the hot platinum is gained by the cold deuterium oxide based on the equation:

Q_{Pt}=-Q_{Deu}

We can represent the heats in terms of mass, heat capacities and temperatures:

m_{Pt}Cp_{Pt}(T_f-T_{Pt})=-m_{Deu}Cp_{Deu}(T_f-T_{Deu})

Thus, we solve for the mass of platinum:

m_{Pt}=\frac{-m_{Deu}Cp_{Deu}(T_f-T_{Deu})}{Cp_{Pt}(T_f-T_{Pt})} \\\\m_{Pt}=\frac{-1.00L*1110g/L*4.211J/(g\°C)*(41.9-25.5)\°C}{0.1256J/(g\°C)*(41.9-200.0)\°C} \\\\m_{Pt}=3860.4g

Next, by using the density of platinum we compute the volume:

V_{Pt}=\frac{3860.4g}{21.45g/cm^3}\\ \\V_{Pt}=180cm^3

Which computed in terms of the edge length is:

V=a^3

Therefore, the edge length turns out:

a=\sqrt[3]{180cm^3}\\ \\a=5.65cm

Best regards.

6 0
3 years ago
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