Answer:
Having difficulties !!! screen shotted it :)
16. H20 - Covalent
17. Mn(NO2)2 - Ionic and called Manganese(II) nitrate
18. HgO - Ionic
19. Li3N - Covalent
B 3-4 is the auto
If it’s needs
This question is missing the part that actually asks the question. The questions that are asked are as follows:
(a) How much of a 1.00 mg sample of americium remains after 4 day? Express your answer using 2 significant figures.
(b) How much of a 1.00 mg sample of iodine remains after 4 days? Express your answer using 3 significant figures.
We can use the equation for a first order rate law to find the amount of material remaining after 4 days:
[A] = [A]₀e^(-kt)
[A]₀ = initial amount
k = rate constant
t = time
[A] = amount of material at time, t.
(a) For americium we begin with 1.00 mg of sample and must convert time to units of years, as our rate constant, k, is in units of yr⁻¹.
4 days x 1 year/365 days = 0.0110
A = (1.00)e^((-1.6x10^-3)(0.0110))
A = 1.0 mg
The decay of americium is so slow that no noticeable change occurs over 4 days.
(b) We can simply plug in the information of iodine-125 and solve for A:
A = (1.00)e^(-0.011 x 4)
A = 0.957 mg
Iodine-125 decays at a much faster rate than americium and after 4 days there will be a significant loss of mass.
<span>The question is asking us "Which of the following would be a result of increased solar activity?"
The Sun is extremely hot, and when it is warm on Earth, the heat has as it source in the Sun. Therefore, an increased solar activity would mean increased temperature on Earth - longer summers and shorter winters, and warmer sea temperatures. The best answer is :
B. Warmer-than-normal sea surface temperatures </span>
Answer:
Isopropylbenzene
Explanation:
If you draw the structure, you can see that there are two methyl groups and in between there.
Adjacent to CH3, there are four neighbouring hydrogens, therefore, n=4+1 = 5. The same is for methyl on other side. For carbon present in benzene ring, there is 2, since there is one hydrogen on benzene per carbon.
