Question:
A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day
.
(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d
(b) How much of excess will be left after one month (1 month = 30 days)
Answer:
a. 
b. 
Step-by-step explanation:
Given
Excess = 6500kwh
Rate = 50kwh/day
Solving (a): E in terms of d
The Excess left (E) in d days is calculated using:
The expression uses minus because there's a reduction in the excess kwh on a daily basis.
Substitute values for Excess, Rate and days
Solving (b); The value of E when d = 30.
Substitute 30 for d in
<em>Hence, there are 5000kwh left after 30 days</em>
Answer:
Step-by-step explanation:
y intercept is <u>8.53 hrs</u>
-0.73(4) + 8.53 = <u>5.61 hrs</u>
slope is -<u>0.73 hr</u>
Answer:
<h3>
1) 7x - 5
</h3><h3>
2) 9y - 18
</h3><h3>
3) 0.5n + 4n
</h3><h3>
4) 2(w³+23)</h3><h3>
Step-by-step explanation:</h3>
1)
The product of seven and a number x: 7·x = 7x
<u>Five less than the product of seven and a number x:</u>
<h3>
7x - 5
</h3>
2)
nine times a number y: 9·y = 9y
<u>The difference of nine times a number y and eighteen:</u>
<h3>
9y - 18
</h3>
3)
half a number n: 0.5n
four times the number: 4·n = 4n
<u>Half a number n increased by four times the number:</u>
<h3>
0.5n + 4n
</h3>
4)
a number w cubed: w³
the sum of a number w cubed and twenty-three: w³+23
<u>Twice the sum of a number w cubed and twenty-three:</u>
<h3>2(
w³+23)</h3>
Answer:
I choose option c hope it helps
Answer:
5 dollars
Step-by-step explanation:
If the price is 90 % off, we will pay 100 - 90 or 10 %
Take the original price times 10 %
50 * 10 %
50 * .10
5
