1) in order to solve this problem you must to obtain The value of K, for it you know by definition that the horizontal slope of the side BC is zero ,
then m = Y2-Y/X2-X1, 0 = 5-K/4-6⇒0 = 5-K⇒K = 5
known this value for K you ca find the equation of thE line that pass through A and C
2) Following the same procedure in first place you calculate the slope with the points A(-2,1) Y C ( 4,5)
m= 5-1/4-(-2) = 2
now with any point A or C and the slope you obtain the line
A(-2,1)
y-y1 = m (x-x1) , Y-1= 2(X-(-2)⇒Y-1= 2X+4⇒Y=2X+4-1⇒Y =2X+3
Answer:
1.120
Step-by-step explanation:
going from small to large milli is 10^-3 L
Answer:
$18.12
Step-by-step explanation:
A pound of raisins=$2
A pound of Almonds=$5.06
x= no. Of pounds of raisins
y=no. Of pounds of almonds
If six pounds of a trail mix contains 2 more pounds of raisins than almonds
Then,
x+y=6
x= 4 pounds
y= 2 pounds
Cost of 6 trail mix=4($2)+2($5.06)
=$8+$10.12
=$18.12
Range in a distribution is the difference between the smallest and the largest value in a distribution. Interquartile range is the difference between the upper quartile and the lower quartile in a distribution.
In an ungrouped data , the first step is to arrange the values in ascending order;
40,41,41,42,43,43,44,44,45,45
The lower quartile is 41 while the upper quartile is 44
Thus the interquartile range is 3 (44-41)
