Trees are important because oxygen
Answer:
25.6 m/s
Explanation:
Draw a free body diagram of the sled. There are two forces acting on the sled:
Normal force pushing perpendicular to the hill
Weight force pulling straight down
Take sum of the forces parallel to the hill:
∑F = ma
mg sin θ = ma
a = g sin θ
a = (9.8 m/s²) (sin 38.0°)
a = 6.03 m/s²
Given:
v₀ = 0 m/s
a = 6.03 m/s²
t = 4.24 s
Find: v
v = at + v₀
v = (6.03 m/s²) (4.24 s) + (0 m/s)
v = 25.6 m/s
Answer:
Lilly's speed is two times John's speed.
Explanation:
m = Mass
a = Acceleration
t = Time taken
u = Initial velocity
v = Final velocity
The force they apply on each other will be equal
![F=ma\\\Rightarrow a_l=\frac{F}{m_l}](https://tex.z-dn.net/?f=F%3Dma%5C%5C%5CRightarrow%20a_l%3D%5Cfrac%7BF%7D%7Bm_l%7D)
![F=ma\\\Rightarrow a_j=\frac{F}{2m_l}\\\Rightarrow a_j=\frac{1}{2}a_l](https://tex.z-dn.net/?f=F%3Dma%5C%5C%5CRightarrow%20a_j%3D%5Cfrac%7BF%7D%7B2m_l%7D%5C%5C%5CRightarrow%20a_j%3D%5Cfrac%7B1%7D%7B2%7Da_l)
![v=u+at\\\Rightarrow v_l=0+\frac{F}{m_l}\times t\\\Rightarrow v_l=a_lt](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20v_l%3D0%2B%5Cfrac%7BF%7D%7Bm_l%7D%5Ctimes%20t%5C%5C%5CRightarrow%20v_l%3Da_lt)
![v=u+at\\\Rightarrow v_l=0+\frac{F}{2m_l}\times t\\\Rightarrow v_j=\frac{1}{2}a_lt\\\Rightarrow v_j=\frac{1}{2}v_l\\\Rightarrow v_l=2v_j](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20v_l%3D0%2B%5Cfrac%7BF%7D%7B2m_l%7D%5Ctimes%20t%5C%5C%5CRightarrow%20v_j%3D%5Cfrac%7B1%7D%7B2%7Da_lt%5C%5C%5CRightarrow%20v_j%3D%5Cfrac%7B1%7D%7B2%7Dv_l%5C%5C%5CRightarrow%20v_l%3D2v_j)
Hence, Lilly's speed is two times John's speed.