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3 years ago

What is the mass, in grams, of 2.00 moles of H2O?

Physics

1 answer:

tia_tia [17]3 years ago

3 0

Answer:

36g

Explanation:

Given parameters:

Number of moles of H₂O = 2moles

Unknown:

Mass of H₂O = ?

Solution:

To solve this problem, use the expression below:

Mass of H₂O = number of moles x molar mass

Molar mass of H₂O = 2(1) + 16 = 18g/mol

Mass of H₂O = 2 x 18 = 36g

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A cannonball is catapulted toward a castle. The cannonball’s velocity when it leaves the catapult is 51.6 m/s at an angle of 37.

Andrei [34K]

Answer:

$v_{y}=35.21m/s$

Explanation:

From the exercise we know the cannonball's initial velocity, the angle which its released with respect to the horizontal and its initial height

$v_{o}=51.6m/s\\\beta =37.0º\\y_{o}=7m$

If we want to know whats the y-component of velocity we need to use the following formula:

$v_{y}^2=v_{oy}^2+ag(y-y_{o})$

Knowing that $g=-9.8m/s^2$

$v_{y}=\sqrt{((51.6m/s)sin(37))^2-2(9.8m/s^2)(0m-7m)}=35.21m/s$

So, the cannonball's y-component of velocity is $v_{y}=35.21m/s$

6 0

3 years ago

Explain the causes of atmospheric pressure and why it changes with altitude?

Verdich [7]

Answer:

As altitude increases, the amount of gas molecules in the air decreases—the air becomes less dense than air nearer to sea level. This is what meteorologists and mountaineers mean by "thin air." Thin air exerts less pressure than air at a lower altitude

4 0

2 years ago

I NEED HELP VERY SOON PLEASE

Igoryamba

I would say d if i was you

7 0

3 years ago

If I measure the current to be 0.5 A and the voltage is 4.5 V. What is my Power?

Korvikt [17]

As we know that P=IV so P = (0.5A)(4.5V)
P= 2.25 watt

6 0

3 years ago

Two points are on a disk turning at constant angular velocity. One point is on the rim and the other halfway between the rim and

DerKrebs [107]

Answer:

The point on the rim

Explanation:

All the points on the disk travels at the same angular speed $\omega$ , since they cover the same angular displacement in the same time. Instead, the tangential speed of a point on the disk is given by

$v=\omega r$

where

$\omega$ is the angular speed

r is the distance of the point from the centre of the disk

As we can see, the tangential speed is directly proportional to the distance from the centre: so the point on the rim, having a larger r than the point halway between the rim and the axis, will have a larger tangential speed, and therefore will travel a greater distance in a given time.

3 0

4 years ago