Acceleration = vf-vi /t
10-22/3=2.6m/s^2
The equation is
s= d/t
In this case you would have to write it out as:
s= 20/5
Speed = 4
Answer:
Heat capacity, Q = 781.74 Joules
Explanation:
Given the following data;
Mass = 12g
Initial temperature = 28.3°C
Final temperature = 43.87°C
Specific heat capacity of water = 4.184J/g°C
To find the quantity of heat needed?
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 43.87 - 28.3
dt = 15.57°C
Substituting into the equation, we have;
Q = 781.74 Joules
A) 10÷8.5
b) 120÷10
c) answer A÷Answer B.
sure on first two, not so sure on C.